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(–4,44 + 60 – 5,56) : (1,2 – 0,8)
= ( 55.56 - 5.56) : 0.4
= 50 : 0,4
= 125
425 . 7 . 4 - 170 . 60
=(425 . 4).7 - 170 . 60
=1700 . 7 - 10200
=11900 - 10200=1700
a) \(255+312+188+645\)
\(=\left(255+645\right)+\left(312+188\right)\)
\(=900+500\)
\(=1400\)
b) \(25+12\cdot5-60\)
\(=25+60-60\)
\(=25\)
c) \(12\cdot75+12\cdot7+12\cdot18\)
\(=12\cdot\left(75+7+18\right)\)
\(=12\cdot100\)
\(=1200\)
d) \(2^4\cdot5-\left[131-\left(13-4\right)^2\right]\)
\(=16\cdot5-\left(131-9^2\right)\)
\(=80-\left(131-81\right)\)
\(=80-50\)
\(=30\)
(44 x 52 x 60) : (11 x 13 x 15)
= 44 x 52 x 60 : 11 : 13 : 15
= (44 : 11) x (52 : 13) x (60 : 15)
= 4 x 4 x 4
= 16 x 4 = 64
Ủng hộ mk nha ^_-
Tính bằng cách hợp lí nhất:
\(\left(44.52.60\right)\div\left(11.13.15\right)\)
\(=\)\(\left(4.11.4.13.4.15\right)\div\left(11.13.15\right)\)
\(=\)\(\left(4.4.4\right).\left(11.13.15\right)\div\left(11.13.15\right)\)
\(=\)\(\left(4.4.4\right)\div1\)
\(=\)\(4.4.4\)
\(=\)\(64\)
\(\frac{44.52.60}{11.13.15}\)
\(=\frac{2^2.11.2^2.13.2^2.15}{11.13.15}\)
\(=2^2.2^2.2^2=4^3=64\)
= 44.52.60 :11:13:15
=(44:11). (52:13). (60:15)
= 4.4.4
=64
\(1+2+3+...+2005+2006=\left[\left(2006-1\right):1+1\right].\left(2006+1\right):2.\)
\(=2006.2007:2\)
\(=2013021\)
\(5+10+...+2000+2005=\left[\left(2005-5\right):5+1\right].\left(2005+5\right):2.\)
\(=401.2010:2\)
\(=403005\)
\(140+136+....+64+60=\left[\left(140-60\right):16+1\right].\left(140+60\right):2.\)
\(=6.200:2\)
\(=600\)
\(3+\frac{1}{5}+128\%+5,56-1-1,67+72\%.\)
\(=\left(3+\frac{1}{5}+5,56-1-1,67\right)+\left(128\%+72\%\right)\)
\(=6,09+200\%=6,09+2=8,09\)
học tốt ~~~
Ta có : \(3+\frac{1}{5}+128\%+5,56-1-1,67+72\%\)
= 3 + \(\frac{1}{5}\)+ \(\frac{128}{100}\)+ \(\frac{556}{100}\)- 1 - \(\frac{167}{100}\)+ \(\frac{72}{100}\)
= \(\frac{300}{100}\)+ \(\frac{20}{100}\)+ \(\frac{128}{100}\)+ \(\frac{556}{100}\)- \(\frac{100}{100}\)-\(\frac{167}{100}\)+\(\frac{72}{100}\)
= \(\frac{809}{100}\)
= 8,09
\(\left(-4,44+60-5,56\right):\left(-2\right)\)
\(=\left(60-10\right):\left(-2\right)\)
\(=\dfrac{50}{-2}=-25\)