Question

[Phùng Kim Thanh]

tính gt biểu thức

A= \(\dfrac{9^5.30^3}{3^{15}.5^3.6^2}\)

B= \(\dfrac{3^{11}.4+3^{11}.5}{3^3.9^5}\)

giúp mik đang cần gấp

Answer 1

[OH-YEAH^^]

A=\(\dfrac{9^5.30^3}{3^{15}.5^3.6^2}=\dfrac{3^{10}.3^3.10^3}{3^{15}.5^3.2^2.3^2}=\dfrac{3^{13}.2^3.5^3}{3^{15}.5^3.2^2.3^2}=\dfrac{2}{3^4}=\dfrac{2}{81}\)

Answer 2

[OH-YEAH^^]

B=\(\dfrac{3^{11}.4+3^{11}.5}{3^3.9^5}=\dfrac{3^{11}.\left(4+5\right)}{3^3.\left(3^2\right)^5}=\dfrac{3^{11}.3^2}{3^3.3^{10}}=1\)