Question

[Hớn Linh]

Tinh gia tri h(x) voi x de da thuc :

\(\left(X+\dfrac{1}{2}\right)^2+1\)

Dat gia tri nho nhat

Answer 1

[♫ DiAmOnD ♫]

Ta có:

\(\left(x+\dfrac{1}{2}\right)^2\)+1\(\ge\)1

mà \(\left(x+\dfrac{1}{2}\right)^2\)\(\ge\)0

Dấu ''='' xảy ra khi:

\(\left(x+\dfrac{1}{2}\right)^2\)=0

=>x+\(\dfrac{1}{2}\)=0

=>x=\(\dfrac{-1}{2}\)

Vậy GTNN của \(\left(x+\dfrac{1}{2}\right)^2\)+1 là 1 khi x=\(\dfrac{-1}{2}\)

Answer 2

[Hớn Linh]

mng oi giup minh voi nhe