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H = (9/30303/80808+7/303030/484848)+4,03
= ( \(\frac{75}{8}+\frac{61}{8}\)) + \(\frac{403}{100}\)
= \(\frac{136}{8}\)+ \(\frac{403}{100}\)
= 17 + \(\frac{403}{100}\)
= \(\frac{2103}{100}\)
Vậy : H = \(\frac{2103}{100}\)
#Chúc bạn học tốt !
\(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\right).\frac{15}{78}=\left(\frac{39}{4}.40\right).\frac{15}{78}=390.\frac{15}{78}=75\)\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03=\left(9\frac{3}{8}+7\frac{30}{48}\right)+4,03=17+4,03=21,03\)
I=10101(5/111111+5/222222+4/3.7.11.13.37)
I=10101(5/111111+5/222222+4/111111)
I=10101(10/222222+5/222222+8/222222)
I=10101.23/222222
I=232323/222222
\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4.03\)
\(H=\left(\frac{75}{8}+\frac{61}{8}\right)+\frac{403}{100}\)
\(H=17+\frac{403}{100}\)
\(H=\frac{2103}{100}\)
\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
\(I=10101.\left(\frac{5}{111111}-\frac{4}{111111}+\frac{5}{222222}\right)\)
\(I=10101.\left(\frac{1}{111111}+\frac{5}{222222}\right)\)
\(I=10101.\frac{7}{222222}\)
\(I=\frac{7}{22}\)
\(H=\left(9\frac{3}{8}+7\frac{3}{8}\right)+4,03=16\frac{3}{8}+4,03=16,375+4,03=20,405\)
\(I=10101.\left(\frac{5}{111111}+\frac{2,5}{111111}-\frac{4}{111111}\right)=10101.\frac{3,5}{111111}=\frac{7}{22}\)
\(A=\left(9+\frac{30303}{80808}+7+\frac{303030}{484848}\right)+4,03\)
\(A=\left(9+\frac{3\times10101}{8\times10101}+7+\frac{30\times10101}{48\times10101}\right)+4,03\)
\(A=\left(9+\frac{3}{8}+7+\frac{5}{8}\right)+4,03\)
\(A=\left(9+7+\frac{3}{8}+\frac{5}{8}\right)+4,03\)
\(A=\left(16+1\right)+4,03\)
\(A=17+4,03=21,03\)