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\(\dfrac{3}{8}+\dfrac{6}{15}:\dfrac{3}{5}\\ =\dfrac{3}{8}+\dfrac{2}{5}.\dfrac{5}{3}\\ =\dfrac{3}{8}+\dfrac{2}{3}\\ =\dfrac{9}{24}+\dfrac{16}{24}\\ =\dfrac{25}{24}\)
a: \(=\dfrac{3}{5}\cdot\dfrac{5}{4}+\dfrac{1}{2}\cdot\dfrac{2}{3}=\dfrac{3}{4}+\dfrac{1}{3}=\dfrac{9+4}{12}=\dfrac{13}{12}\)
b: \(\Leftrightarrow x\cdot\dfrac{5}{4}=\dfrac{5}{8}\)
hay x=1/2
1/10 + 3/5 : 2/3
=1/10 + 9/10
=10/10
=1
\((\)6/8 -2/6\()\) x 1/2
=18/48 X 1/2
=3/7 x 1/2
=2/14
\(\dfrac{1}{10}\) + \(\dfrac{3}{5}\):\(\dfrac{2}{3}\)
= \(\dfrac{1}{10}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{3}{2}\)
= \(\dfrac{1}{10}\) + \(\dfrac{9}{10}\)
= \(\dfrac{10}{10}\)
= 1
( \(\dfrac{6}{8}\) - \(\dfrac{2}{6}\)) \(\times\) \(\dfrac{1}{2}\)
=( \(\dfrac{18}{24}\) - \(\dfrac{8}{24}\)) \(\times\) \(\dfrac{1}{2}\)
= \(\dfrac{10}{24}\) \(\times\) \(\dfrac{1}{2}\)
= \(\dfrac{5}{24}\)
a, 2 \(\times\) \(\dfrac{2}{4}\) : \(\dfrac{4}{5}\) b, \(\dfrac{7}{8}\) \(\times\) \(\dfrac{4}{5}\) : 3
= 1 : \(\dfrac{4}{5}\) = \(\dfrac{7}{10}\) : 3
= 1 \(\times\) \(\dfrac{5}{4}\) = \(\dfrac{7}{10}\) \(\times\) \(\dfrac{1}{3}\)
= \(\dfrac{5}{4}\) = \(\dfrac{7}{30}\)
\(2\times\dfrac{2}{4}:\dfrac{4}{5}\)
\(=1:\dfrac{4}{5}\)
\(=1\times\dfrac{5}{4}\)
\(=\dfrac{5}{4}\)
__________________________
\(\dfrac{7}{8}\times\dfrac{4}{5}:3\)
\(=\dfrac{7}{2}\times\dfrac{1}{5}:3\)
\(=\dfrac{7}{10}\times\dfrac{1}{3}\)
\(=\dfrac{7}{30}\)
Chúc bạn học tốt:>
\(=\dfrac{3}{5}+\dfrac{8}{15}:\dfrac{2}{7}=\dfrac{3}{5}+\dfrac{28}{15}=\dfrac{9}{15}+\dfrac{28}{15}=\dfrac{37}{15}\)
\(=\dfrac{7}{8}+\dfrac{7}{3}-\dfrac{11}{12}=\dfrac{77}{24}-\dfrac{11}{12}=\dfrac{55}{24}\)
Lời giải:
a.
$\frac{5}{15}-\frac{1}{6}\times \frac{2}{5}=\frac{5}{15}-\frac{1}{15}=\frac{4}{15}$
b.
$\frac{8}{24}+\frac{3}{4}:\frac{1}{8}=\frac{1}{3}+6=\frac{19}{3}$
c.
$\frac{1}{7}: \frac{2}{8}-\frac{1}{7}=\frac{1}{7}\times 4-\frac{1}{7}$
$=\frac{1}{7}\times (4-1)=\frac{1}{7}\times 3=\frac{3}{7}$