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a) \(\dfrac{2^6\cdot5^5}{10^5}\)
\(=\dfrac{2^6\cdot5^5}{2^5\cdot5^5}\)
\(=2\)
b) \(\dfrac{3^6\cdot5^7}{15^6}\)
\(=\dfrac{3^6\cdot5^7}{3^6\cdot5^6}\)
\(=5\)
a) 25.23 − 32 + 125 = 25.8 – 9 + 125 = 316.
b) 2.32 + 5.(2 + 3) = 2.9+5.5 = 43.
a) \(3\cdot4\cdot25\cdot8\cdot125\)
\(=\left(125\cdot8\right)\cdot\left(4\cdot25\right)\cdot3\)
\(=1000\cdot100\cdot3\)
\(=300000\)
b) \(36\cdot63+64\cdot663\)
\(=63\cdot\left(36+64\right)\)
\(=63\cdot100\)
\(=6300\)
c) \(45\cdot129+71\cdot129\)
\(=129\cdot\left(129+71\right)\)
\(=129\cdot200\)
\(=25800\)
d) \(26\cdot\left(43+57\right)+74\cdot\left(43+57\right)\)
\(=26\cdot100+74\cdot100\)
\(=2600+7400\)
\(=10100\)
a) 3.4.25.8.125
=3(4.25).(8.125)
=3.100.1000
300000
b) 36.63+ 64.63
=(36+64).63
=100.63
=6300
c) 45.129+ 71.45
=45.(129+71)
=45.200
=9000
d) 26. (43+ 57)+ 74(57 +43)
=26.43+26.57 + 74.57 + 74.43
=(26.43+74.43)+(26.57 + 74.57 )
= [43.(26+74)]+[ (26+74).57]
=[43.100]+[100.57]
=4300+5700
= 10000
\(=\dfrac{2}{3}+\dfrac{1}{3}.\left(\dfrac{7}{18}\right):\dfrac{7}{12}\)
\(=\dfrac{2}{3}+\dfrac{7}{54}:\dfrac{7}{12}\)
\(=\dfrac{2}{3}+\dfrac{2}{9}\)
\(=\dfrac{8}{9}\)
a) Cách 1: Thay x = 7, ta có:
(23 + x) - (56 - x)
= (23 + 7) - (56 - 7)
= 30 - 49
= -19
Cách 2:
Thay x = 7, ta có:
(23 + x) - (56 - x)
= (23 + 7) - (56 - 7)
= 23 + 7 - 56 + 7
= 30 - 56 + 7
= (-26) + 7
=-19.
b) Cách 1: Thay x = 13, y = 11, ta có:
25 - x - (29 + y - 8)
= 25 - 13 - (29 + 11 - 8)
= 12 - 32
= -20.
Cách 2: Thay x = 13, y = 11, ta có:
25 - x - (29 + y - 8)
= 25 - 13 - (29 + 11 - 8)
= 25 - 13 - 29 - 11 + 8
= 12 - 29 - 11 + 8
= (-17) - 11 + 8
= (-28) + 8
=-20.
A= \(\dfrac{1}{1.3}\)+\(\dfrac{1}{3.5}\)+\(\dfrac{1}{5.7}\)+\(\dfrac{1}{7.9}\)+...+\(\dfrac{1}{97.99}\)
2A= 1 - \(\dfrac{1}{3}\)+\(\dfrac{1}{3}\) - \(\dfrac{1}{5}\)+\(\dfrac{1}{5}\) - \(\dfrac{1}{7}\)+\(\dfrac{1}{7}\) - \(\dfrac{1}{9}\)+...+\(\dfrac{1}{97}\)-\(\dfrac{1}{99}\)
2A= 1-\(\dfrac{1}{99}\)
2A= \(\dfrac{98}{99}\)
A= \(\dfrac{98}{99}\) : 2
A=\(\dfrac{49}{99}\)
A=0
B=2015.2016(2016-2015)
= 2047240
Tại sao A=0