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2,
a) \(315-\left(135-x\right)=215\)
\(\Rightarrow135-x=315-215\)
\(\Rightarrow135-x=100\)
\(\Rightarrow x=135-100\)
\(\Rightarrow x=35\)
b) \(x-320:32=25\cdot16\)
\(\Rightarrow x-10=5^2\cdot4^2\)
\(\Rightarrow x-10=20^2\)
\(\Rightarrow x-10=400\)
\(\Rightarrow x=410\)
c) \(3\cdot x-2018:2=23\)
\(=3\cdot x-1009=23\)
\(\Rightarrow3\cdot x=1032\)
\(\Rightarrow x=1032:3\)
\(\Rightarrow x=344\)
d) \(280-9\cdot x-x=80\)
\(\Rightarrow280-x\cdot\left(9+1\right)=80\)
\(\Rightarrow280-10\cdot x=80\)
\(\Rightarrow10\cdot x=280-80\)
\(\Rightarrow10\cdot x=200\)
\(\Rightarrow x=20\)
e) \(38\cdot x-12\cdot x-x\cdot16=40\)
\(\Rightarrow x\cdot\left(38-12-16\right)=40\)
\(\Rightarrow x\cdot10=40\)
\(\Rightarrow x=40:10\)
\(\Rightarrow x=4\)
A = \(\dfrac{18}{26}\) + (-\(\dfrac{5}{27}\)) + (-\(\dfrac{22}{86}\)) + \(\dfrac{12}{39}\) - \(\dfrac{32}{43}\)
A = \(\dfrac{9}{13}\) - \(\dfrac{5}{27}\) - \(\dfrac{11}{43}\) + \(\dfrac{4}{13}\) - \(\dfrac{32}{43}\)
A = (\(\dfrac{9}{13}\) + \(\dfrac{4}{13}\)) - (\(\dfrac{11}{43}\) + \(\dfrac{32}{43}\)) - \(\dfrac{5}{27}\)
A = \(\dfrac{13}{13}\) - \(\dfrac{43}{43}\) - \(\dfrac{5}{27}\)
A = 1 - 1 - \(\dfrac{5}{27}\)
A = 0 - \(\dfrac{5}{27}\)
A = - \(\dfrac{5}{27}\)
a)
\(15+27+9+85+73\)
\(=\left(15+85\right)+\left(27+73\right)+39\)
\(=200+39\)
\(=329\)
b)
\(54.36+54.27+54.37\)
\(=54\left(36+27+37\right)\)
\(=54.100\)
\(=5400\)
c)
\(168-3^7:3^4+2013^0\)
\(=168-3^3+1\)
\(=168-27+1\)
\(=142\)
d)
\(3^4.15+81.26+27.59.3\)
\(=81.15+81.26+81.59\)
\(=81.\left(15+26+59\right)\)
\(=81.100\)
\(=8100\)
Tính giá trị của các biểu thức sau :
a.15 + 27 + 39 + 85 + 73
= ( 15 + 85 ) + ( 27 + 73 ) + 39
= 100 + 100 + 39
= 200 + 39
= 239
b. 54 .36 + 54 . 27 + 54 . 37
= 54 . ( 36 + 27 + 37 )
= 54 . 100
= 5400
c.168 - 37 : 34 + 20130
= 168 - 33 + 1
= 168 - 27 + 1
= 141 + 1
= 142
đ. 34 . 15 + 81 . 26 + 27 . 59 . 3
= 34 . 15 + 34 . 26 + 34 . 59
= 34 . ( 15 + 26 + 59 )
= 81 . 100
= 8100
a, 15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0
= 15.{32:[1+15]+3}–1
= 15.5–1
= 74
b, 25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }
= 25.{128:[8+4.2]–16}
= 25.24
= 600
c, 2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }
= 2019.{101–1000:[(32+125–36):11–1]}
= 2019.{101–1000:[121:11–1]}
= 2019.{101–1000:10}
= 2019.1
= 2019
a) 12.18 + 14.3 – 255:17
= 216 + 42 – 15
= 273
b) 13 + 42.5 – (198:11 – 8)
= 13 + 210 – 10
= 213
c) 25.8 – 12.5 + 272:17 – 8
= 200 – 60 +16 – 8
= 148
d, 2 3 - 5 3 : 5 2 + 12 . 2 2
= 8 – 5 +48
= 51
a)\(\frac{15\times3^5}{27^3\times10^2}=\frac{5\times3^6}{3^9\times5\times20}=\frac{1}{3^3\times20}=\frac{1}{540}\)
b) đề thiếu
c) \(\frac{81^{14}\times3^{17}}{27^{10}\times9^{15}}=\frac{\left(9^2\right)^{14}\times3^{17}}{3^{10}\times9^{10}\times9^{15}}=\frac{9^{28}\times3^{17}}{3^{10}\times9^{25}}=\frac{9^3\times3^7}{1}=1594323\)
xin lỗi!phần b là 32^2