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( 198 : 18 - 143 : 13 ) x ( 16996 - 1110 : 30 x 305 )
= ( 11 - 11 ) x ( 16996 - 1110 : 30 x 305 )
= 0 x ( 16996 - 1110 : 30 x 305 )
= 0
(158 + 144) x 32 - 294 = 302 x 32 - 294 = 9664 - 294 = 9370
4510 - 255 + (198 + 81 x 21) = 4510 - 225 + (198 + 1701) = 4285 + 1899 = 6184
83 489 - 75 x 26 = 83 489 - 1950 = 81 539
Ta có:
\(A=\left(1-\frac{1}{1.2}\right)+\left(1-\frac{1}{2.3}\right)+....+\left(1-\frac{1}{2016.2017}\right)\)
\(=\left(1+1+...+1\right)-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2016.2017}\right)\)
\(=2016-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2016}-\frac{1}{2017}\right)\)
\(=2016-\left(1-\frac{1}{2017}\right)\)
\(=2016-\frac{2016}{2017}=\frac{4064256}{2017}\)
Vậy giá trị biểu thức là \(\frac{4064256}{2017}\)
=(198 : 2) x 444 x 2 x 132) : 25) / 33) x 8888) : 5) x 66) : 125) x 5 =66009449.5949
\(\frac{5}{6}+\frac{4}{5}+\frac{2}{5}\)
\(=\frac{49}{30}+\frac{2}{5}\)
\(=\frac{61}{30}\)
\(\frac{5}{6}+\frac{4}{5}+\frac{2}{5}=\frac{5}{6}+\frac{6}{5}=\frac{61}{30}\)
\(\frac{2016,2017-198}{2017.2015+1819}=\frac{\left(2015+1\right).2017-198}{2017.2015+1819}\)
\(=\frac{2015.2017+2017-198}{2017.2015+1819}\)
\(=\frac{2015.2017+1819}{2017.2015+1819}\)
\(=1\)
Nhớ k cho mình nha
\(\frac{2016.2017-198}{2017.2015+1819}=\frac{\left(2015+1\right)2017-198}{2017.2015+1819}=\frac{2015.2017+2017-198}{2017.2015+1819}=\frac{2017.2015+1819}{2017.2015+1819}=1\)