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\(A=1-1-\dfrac{5}{6}+1+\dfrac{7}{12}-1-\dfrac{9}{20}+1+\dfrac{11}{30}-1-\dfrac{13}{42}+1+\dfrac{15}{56}-1-\dfrac{17}{72}+1+\dfrac{19}{90}\)
\(=1-\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{9}+\dfrac{1}{10}\)
=1/2+1/10
=5/10+1/10=6/10=3/5
1/2+5/6+11/12+19/20+29/30+41/42+55/56
= 1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/90
= 9-(1/2+1/6+1/12+1/20+1/42+1/58+1/72+1/90)
=9-( 1/1.2 + 1/2.3 +1/3.4 +1/4.5 +1/5.6+ 1/6.7 +1/7.8 +1/8.9 +1/9.10)
=9-(1 -1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)
=9-(1 -1/10)
=9-(9/10)= 81/10=8,1
Bài 1: Bạn xem lại đã viết đúng đề chưa vậy.
Bài 2:
$P=29-|16+3.2|+1=29-|22|+1=29-22+1=7+1=8$
Phân tích ra bình thường pạn ạ
5.4^15.9^9-4.3^20.8^9
5.2^9.6^19-7.2^29.27^6
= 5.2^30.3^18-2^2.3^20.2^27
5.2^9.2^19.3^19-7.2^29.3^18
= 2^29.3^18(5.2-3^2)
2^28.3^18(5.3-7.2)
= 2^29.3^18
2^28.3^18
=2
Cái 4^15=2^30 là 4^15=(2^2)^15= 4^15
Những cái sau Tương tự pạn nhé
Ta có: \(A=\dfrac{5\cdot\left(2^2\cdot3^2\right)^9\cdot\left(2^2\right)^6-2\cdot\left(2^2\cdot3\right)^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}-7\cdot2^{29}\cdot3^{18}}\)
\(=\dfrac{5\cdot2^{18}\cdot3^{18}\cdot2^{12}-2\cdot2^{28}\cdot3^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}-7\cdot2^{28}\cdot3^{18}\cdot2}\)
\(=\dfrac{5\cdot2^{30}\cdot3^{18}-2\cdot2^{28}\cdot3^{18}}{2^{28}\cdot3^{18}\cdot\left(5-7\cdot2\right)}\)
\(=\dfrac{2^{28}\cdot3^{18}\cdot\left(5\cdot2^2-2\right)}{2^{28}\cdot3^{18}\cdot\left(5-14\right)}\)
\(=\dfrac{20-2}{-9}=\dfrac{18}{-9}=-2\)
\(\dfrac{2^7\cdot3^8}{6^6}\)
\(=\dfrac{2^7\cdot3^8}{2^6\cdot3^6}\)
\(=2\cdot3^2\)
\(=2\cdot9\)
\(=18\)
− 29 .6 : 6 = − 29 .6 : 6 = − 29