\(\frac{8^{10}.15^{16}}{12^{15}.25^8}\)

 

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2 tháng 11 2019

Ta có: \(\frac{8^{10}.15^{16}}{12^{15}.25^8}=\frac{\left(2^3\right)^{10}.\left(3.5\right)^{16}}{\left(2.2.3\right)^{15}.\left(5^2\right)^8}\)

                              \(=\frac{2^{30}.3^{16}.5^{16}}{2^{15}.2^{15}.3^{15}.5^{16}}\)

                             \(=\frac{2^{30}.3^{16}.5^{16}}{2^{30}.3^{15}.5^{16}}\)

                              \(=\frac{3^{16}}{3^{15}}\)

                             \(=3\)

Học tốt nha^^

2 tháng 11 2019

ra 24 bạn tách các số ra và rút gọn

9 tháng 7 2019

\(\frac{60^8}{12^7.5^8}=\frac{2^{16}.3^8.5^8}{2^{14}.3^7.5^8}=\frac{2^2.3}{1}=12\)

\(\frac{50^{15}.13^{18}}{25^7.26^{15}.5^{16}}=\frac{2^{15}.5^{30}.13^{18}}{5^{30}.2^{15}.13^{15}}=2197\)

\(\frac{10^4}{5^3}=\frac{5^4.2^4}{5^3}=80\)

9 tháng 7 2019

\(\frac{60^8}{12^7.5^8}=\frac{2^3.3}{1}=12\)

\(\frac{50^{15}.13^{18}}{25^7.26^{15}}=2197\)

\(10^4:5^3=10000:125=80\)

4 tháng 10 2021

yutyugubhujyikiu

5 tháng 12 2015

\(20\frac{15}{16}.16\frac{8}{9}-20\frac{15}{16}.12\frac{8}{9}\)

\(=20\frac{15}{16}.\left(16\frac{8}{9}-12\frac{8}{9}\right)\)

\(=20\frac{15}{16}.4\)

\(=83\frac{3}{4}\)

12 tháng 10 2018

1.(2515.415)/(517.2016)=(530.230)/(517.516.232)=1/(53.22)=1/500

2.a,-x/2=8/-x=>-x.(-x)=2*8 =>x^2=16=(-4)^2=4^2

=>x=4 hoặc x=-4

b,(3/4)2x/(2/5)10=(15/8)10

(3/4)2x=(2/5*15/8)10

(3/4)2x=(3/4)10

2x=10

x=5

12 tháng 10 2018

1)  \(\frac{25^{15}\cdot4^{15}}{5^{17}\cdot20^{16}}\)

\(=\frac{5^{30}\cdot2^{30}}{5^{33}\cdot2^{32}}\)

\(=\frac{1}{5^3\cdot2^2}\)

\(=\frac{1}{500}\)

2) 

a) \(\frac{-x}{2}=\frac{8}{-x}\)

\(\Rightarrow\left(-x\right)\left(-x\right)=8\cdot2\)

\(\Rightarrow x^2=16\)

\(\Rightarrow x=\left\{\pm4\right\}\)

17 tháng 10 2016

a) \(\frac{7}{15}+\frac{9}{10}+\frac{8}{15}-\frac{-1}{10}-\frac{20}{10}+\frac{1}{157}\)

\(=\frac{7}{15}+\frac{9}{10}+\frac{8}{15}+\frac{1}{10}-\frac{20}{10}+\frac{1}{157}\)

\(=\left(\frac{7}{15}+\frac{8}{15}\right)+\left(\frac{9}{10}+\frac{1}{10}\right)-2+\frac{1}{157}\)

\(=1+1-2+\frac{1}{157}\)

\(=2-2+\frac{1}{157}\)

\(=0+\frac{1}{157}=\frac{1}{157}\)

b) \(\frac{1}{13}+\frac{16}{7}+\frac{3}{105}-\frac{9}{7}-\frac{-12}{13}\)

\(=\frac{1}{13}+\frac{16}{7}+\frac{1}{35}-\frac{9}{7}+\frac{12}{13}\)

\(=\left(\frac{1}{13}+\frac{12}{13}\right)+\left(\frac{16}{7}-\frac{9}{7}\right)+\frac{1}{35}\)

\(=1+1+\frac{1}{35}\)

\(=2+\frac{1}{35}\)

\(=\frac{70}{35}+\frac{1}{35}=\frac{71}{35}\)

25 tháng 7 2017

\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)

\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)

\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)

\(=3-\left(-1\right)\)

\(=4\)

b)   \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)

       \(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)

     \(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)

      \(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)

    \(=\frac{199}{16}:\left(12-2\right)\)

\(=\frac{199}{16}:10\)

\(=\frac{199}{160}\)

c)   \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)

\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)

\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)

\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)

\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)

     

25 tháng 7 2017

giờ mk phải đi ngủ r mai mk làm cho 

20 tháng 12 2019

a) Ta có: \(25^{15}=\left(5^2\right)^{15}=5^{30}\)

               \(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}\)\(=2^{30}.3^{30}=6^{30}\)

Vì \(5^{30}< 6^{30}\)nên \(25^{15}< 8^{10}.3^{30}\)

b) Ta có: \(\frac{4^{15}}{7^{30}}=\frac{\left(2^2\right)^{15}}{7^{30}}=\frac{2^{30}}{7^{30}}\)

\(\frac{8^{10}.3^{30}}{7^{30}.4^{15}}=\frac{\left(2^3\right)^{10}.3^{30}}{7^{30}.\left(2^2\right)^{15}}=\frac{2^{30}.3^{30}}{7^{30}.2^{30}}=\frac{3^{30}}{7^{30}}\)

Vì \(2^{30}< 3^{30}\)nên \(\frac{2^{30}}{7^{30}}< \frac{3^{30}}{7^{30}}\)hay \(\frac{4^{15}}{7^{30}}< \frac{8^{10}.3^{30}}{7^{30}.4^{15}}\)

_Học tốt_