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19 tháng 4 2017

ta có: \(B=\frac{1}{10.9}+\frac{1}{18.13}+\frac{1}{26.17}+...+\frac{1}{802.405}\)

              \(=\frac{1}{2}.\left(\frac{1}{5.9}+\frac{1}{9.13}+\frac{1}{13.17}+...+\frac{1}{401.405}\right)\)

               \(=\frac{1}{2}.\frac{1}{4}.\left(\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{401.405}\right)\)

                \(=\frac{1}{8}.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{17}-...-\frac{1}{401}+\frac{1}{405}\right)\)

                 \(=\frac{1}{8}.\left(\frac{1}{5}-\frac{1}{405}\right)\)

                  \(=\frac{1}{8}.\frac{80}{405}=\frac{10}{405}=\frac{2}{81}\)

5 tháng 1 2018

 = 7/4.(4/1.5 + 4/5.9 + 4/9.13 + 4/13.17 + 4/17.21)

 = 7/4.(1-1/5+1/5-1/9+1/9-1/13+1/13-1/17+1/17-1/21)

 = 7/4.(1-1/21)

 = 7/4.20/21 = 5/3

Tk mk nha

5 tháng 1 2018

Đặt biểu thức bằng A

4/7A=1-1/5+1/5-1/9+...+1/17_1/21

4/7A=1-1/21

4/7A=20/21

A=35/21=5/3

5 tháng 4 2018

Áp dụng theo dạng toán số ai cập ta có:

4/1.5+4/5.9+4/9.13+4/13.17+4/17.21=1/1-1/5+1/5-1/9+1/9-1/13+1/13-1/17+1/17-1/21=1-1/21 < 1

Vậy tổng đó < 1

13 tháng 4 2019

A=\((\frac{1}{3.8}+\frac{1}{8.13}+...+\frac{1}{33.38})\)

A=\(\frac{1}{5}\left(\frac{5}{3.8}+\frac{5}{8.13}+...+\frac{5}{33.38}\right)\)

A=\(\frac{1}{5}\left(\frac{1}{3}-\frac{1}{8}+\frac{1}{8}-\frac{1}{13}+...+\frac{1}{33}-\frac{1}{38}\right)\)

A=\(\frac{1}{5}.\left(\frac{1}{3}-\frac{1}{38}\right)\)

A=\(\frac{1}{5}.\frac{35}{114}\)

A=\(\frac{7}{114}\)

B=\((\frac{1}{3.10}+\frac{1}{10.17}+...+\frac{1}{31.38})\)

B=\(\frac{1}{7}\left(\frac{7}{3.10}+\frac{7}{10.17}+...+\frac{7}{31.38}\right)\)

B=\(\frac{1}{7}\left(\frac{1}{3}-\frac{1}{10}+\frac{1}{10}-\frac{1}{17}+...+\frac{1}{31}-\frac{1}{38}\right)\)

B=\(\frac{1}{7}\left(\frac{1}{3}-\frac{1}{38}\right)\)

B=\(\frac{1}{7}.\frac{35}{114}\)

B=\(\frac{5}{114}\)

\(\frac{A}{B}\)=\(\frac{7}{114}:\frac{5}{114}=\frac{7}{114}.\frac{114}{5}=\frac{7}{5}\)

Vậy \(\frac{A}{B}=\frac{7}{5}\)

13 tháng 4 2019

A = \(\frac{1}{3}-\frac{1}{8}+\frac{1}{8}-\frac{1}{13}+....+\frac{1}{33}-\frac{1}{38}\)

=\(\frac{1}{3}-\frac{1}{38}\)

=\(\frac{35}{114}\)

B =\(\frac{1}{3}-\frac{1}{10}+\frac{1}{10}-\frac{1}{17}+...+\frac{1}{31}-\frac{1}{38}\)

=\(\frac{1}{3}-\frac{1}{38}\)

=\(\frac{35}{114}\)

=>tỉ số \(\frac{A}{B}\)= \(\frac{35}{114}:\frac{35}{114}\)=1

8 tháng 8 2019

\(\frac{1}{1\cdot9}+\frac{1}{9\cdot17}+...+\frac{1}{x\left(x+8\right)}=\frac{29}{410}\)

\(\frac{8}{1\cdot9}+\frac{8}{9\cdot17}+...+\frac{8}{x\left(x+8\right)}=\frac{116}{205}\)

\(\frac{1}{1}-\frac{1}{9}+\frac{1}{9}-\frac{1}{17}+...+\frac{1}{x}-\frac{1}{x+8}=\frac{116}{205}\)

\(1-\frac{1}{x+8}=\frac{116}{205}\)

\(\frac{x+8}{x+8}-\frac{1}{x+8}=\frac{116}{205}\)

\(\frac{x+7}{x+8}=\frac{116}{205}\)

\(\Leftrightarrow\text{ }205\left(x+7\right)=116\left(x+8\right)\)

\(205x+1435=116x+928\)

\(116x-205x=1435-928\)

\(-89x=507\)

\(x=-5\frac{62}{89}\)

tách vế trái đặt là A\(A=\frac{1}{1.9}+\frac{1}{9.17}+...+\frac{1}{x.\left(x+8\right)}\)

\(A=\frac{1}{1}-\frac{1}{9}+\frac{1}{9}-\frac{1}{17}+...+\frac{1}{x}-\frac{1}{x+8}\)

\(A=\frac{1}{1}-\frac{1}{x+8}\)

thay \(\frac{1}{1}-\frac{1}{x+8}=\frac{29}{410}\)

\(\frac{1}{x+8}=\frac{1}{1}-\frac{29}{410}=\frac{410}{410}-\frac{29}{410}\)

\(\frac{1}{x+8}=\frac{381}{410}\)

hình như sai ở đâu

1 tháng 7 2018

Sửa đề : \(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)

\(\Leftrightarrow\)\(\frac{2}{42}+\frac{2}{56}+\frac{2}{72}+...+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)

\(\Leftrightarrow\)\(2\left(\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{2}{9}\)

\(\Leftrightarrow\)\(2\left(\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{2}{9}\)

\(\Leftrightarrow\)\(2\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{2}{9}\)

\(\Leftrightarrow\)\(2\left(\frac{1}{6}-\frac{1}{x+1}\right)=\frac{2}{9}\)

\(\Leftrightarrow\)\(\frac{1}{6}-\frac{1}{x+1}=\frac{2}{9}.\frac{1}{2}\)

\(\Leftrightarrow\)\(\frac{1}{6}-\frac{1}{x+1}=\frac{1}{9}\)

\(\Leftrightarrow\)\(\frac{1}{x+1}=\frac{1}{6}-\frac{1}{9}\)

\(\Leftrightarrow\)\(\frac{1}{x+1}=\frac{1}{18}\)

\(\Leftrightarrow\)\(x+1=18\)

\(\Leftrightarrow\)\(x=18-1\)

\(\Leftrightarrow\)\(x=17\)

Vậy \(x=17\)

Chúc bạn học tốt ~ 

1 tháng 7 2018

\(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)

\(\Leftrightarrow\)\(x+10\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{53.55}\right)=\frac{3}{11}\)

\(\Leftrightarrow\)\(x+10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)

\(\Leftrightarrow\)\(x+10\left(\frac{1}{11}-\frac{1}{55}\right)=\frac{3}{11}\)

\(\Leftrightarrow\)\(x+10.\frac{4}{55}=\frac{3}{11}\)

\(\Leftrightarrow\)\(x+\frac{40}{55}=\frac{3}{11}\)

\(\Leftrightarrow\)\(x=\frac{3}{11}-\frac{40}{55}\)

\(\Leftrightarrow\)\(x=\frac{-5}{11}\)

Vậy \(x=\frac{-5}{11}\)

Chúc bạn học tốt ~ 

6 tháng 8 2016

\(\frac{4}{1\cdot3\cdot5}+\frac{4}{3\cdot5\cdot7}+\frac{4}{5\cdot7\cdot9}+\frac{4}{7\cdot9\cdot11}+\frac{4}{9\cdot11\cdot13}\)

\(=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)

\(=\frac{1}{1.3}-\frac{1}{11.13}\)

\(=\frac{1}{3}-\frac{1}{143}\)

\(=\frac{140}{429}\)

4 tháng 8 2018

\(b)\) Ta có: \(x-\frac{37}{45}=\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45\text{ }}\)

\(\Leftrightarrow x-\frac{37}{45}=\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{41}-\frac{1}{45}\)

\(\Leftrightarrow x-\frac{37}{45}=\frac{1}{5}-\frac{1}{45}\)

\(\Leftrightarrow x-\frac{37}{45}=1\)

\(\Leftrightarrow x=1+\frac{37}{45}\)

\(\Leftrightarrow x=\frac{82}{45}\)

Vậy \(x=\frac{82}{45}\)

4 tháng 8 2018

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