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\(\dfrac{10^3+2.5^3+5^3}{55}=\dfrac{\left(2.5\right)^3+2.5^3+5^3}{55}=\dfrac{2.5^3+2.5^3+5^3}{55}=\dfrac{5^3\left(2+2+1\right)}{55}=\dfrac{5^2.5}{11}=\dfrac{5^3}{11}=\dfrac{125}{11}\)
\(\dfrac{10^3+2.5^3+5^3}{55}=\dfrac{\left(2.5\right)^3+2.5^3+5^3}{55}\)
\(\Rightarrow\)\(\dfrac{5^3\left(2+2+2\right)}{55}\)=\(\dfrac{5^3}{11}\)=\(\dfrac{125}{11}\)
\(=\dfrac{5^3\left(2^3+2+1\right)}{55}-\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=5^2-\dfrac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\left(2\cdot3-1\right)}=25-\dfrac{2}{3}\cdot\dfrac{6}{5}\)
=25-4/5
=24,2
chìu mk lm nha
Giờ mk có việc rồi
Nhớ tick cho mk nha !!!!!
Lần sau bạn nên viết đề rõ hơn nhé!
Đề: Tính nhanh: \(\frac{10^3+2\cdot5^3+5^3}{55}\)
ta có: \(\frac{10^3+2\cdot5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{5\cdot11}=\frac{5^3\cdot11}{5\cdot11}=5^2=25\)
Học tốt nhé ^3^
\(\frac{10^3+2\cdot5^3+5^3}{55}\)
\(=\frac{\left(5.2\right)^3+5^3\cdot\left(2+1\right)}{55}\)
\(=\frac{5^3\cdot2^3+5^3\cdot3}{55}\)
\(=\frac{5^3\cdot8+5^3\cdot3}{55}\)
\(=\frac{5^3\cdot\left(8+3\right)}{55}\)
\(=\frac{5^3\cdot11}{55}=\frac{5^3}{5}=5^2=25\)
Tick nha
103+2.53+53:55
= 1000+2.125+125:55
= 1000+250+25/11
= \(1252\frac{3}{11}\)
a)\(\frac{10^3+2.5^3+5^3}{55}\)=\(\frac{5^3.2^3+2.5^3+5^3}{5.11}\)=\(\frac{5^3.\left(2^3+2+1\right)}{5.11}\)=\(5^2\)=\(25\)
b) \(2^x+2^{x+3}=144\)
\(\Rightarrow2^x+2^x.2^3=144\)
\(\Rightarrow2^x.\left(1+2^3\right)=144\)
\(\Rightarrow2^x=16=2^4\)
\(\Rightarrow x=4\)
c) \(2\left(x-5\right)+3\left(x-7\right)=10\)
\(\Rightarrow2x-10+3x-21=10\)
\(\Rightarrow5x-31=10\)
\(\Rightarrow5x=41\)
\(\Rightarrow x=\frac{41}{5}=8,2\)
Ta có:
\(\frac{10^{3^{ }}+2.5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{55}=\frac{5^3.11}{55}=25\)
từ b1 qua b2 chi tiết hơn đc ko bn