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C1: = (36/6 —4/6+3/6) — (30/6+10/6–9/6)—(18/6–14/6+15/6)
= 35/6–31/6–19/6=-15/6=-5/2
C2:= 6–2/3+1/2–5–5/3+3/2–3+7/3–5/2
=(6–5–3)+(-2/3+5/3–7/3)+(1/2+3/2-5/2)
=-2 + 0 +(-1/2)= -5/2
Cách 1: = ( 36/6 - 4/6 + 3/6 ) - ( 30/6 + 10/6 - 9/6 ) - ( 18/6 - 14/6 + 15/6 )
= 35/6 - 31/6 - 19/6
= -5/2
Cách 2: = 6 - 2/3 + 1/2 - 5 - 5/3 + 3/2 -3 + 7/3 - 5/2
= ( 6 - 5 - 3 ) + ( -2/3 - 5/3 + 7/3 ) + ( 1/2 + 3/2 - 5/2 )
= -2 + 0 + -1/2
= -5/2
Tính bằng 2 cách:
A= (3-1/4+2/3) - (5+1/3-6/5) - (6-7/4+3/2)
Giúp mk nghen! Mai mk phải nộp bài rùi!!!
\(A=3-\frac{1}{4}+\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(=3-6-5+\frac{7-1}{4}+\frac{2-1}{3}-\frac{3}{2}+\frac{6}{5}=-8+\frac{3}{2}+\frac{1}{3}-\frac{3}{2}+\frac{6}{5}=-8+\frac{1}{3}+\frac{6}{5}=-\frac{97}{15}\)
C1: A= (36/6+4/6+3/6)-(30/6+10/6-9/6)-(18/6-14/6+15/6)
=43/6-31/6-19/6
=-7/6
C2: A = 6-2/3+1/2-5-5/3+3/2-3+7/3-5/2
=(6-5-3)+(2/3-5/3+7/3)+(1/2+3/2-5/2)
=-2+4/3+(-1/2)
=-12/6+8/6+(-3/6)
=-7/6
\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)
\(=-2+2-\frac{5}{2}\)
\(=-\frac{5}{2}\)
Cách 2 là bạn tính trong ngoặc trước ,ngoài ngoạc sau (tự làm nhé)
Làm tiếp cách 2 Secret Person
\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(A=\left(\frac{36}{6}-\frac{4}{6}+\frac{3}{6}\right)-\left(\frac{150}{30}+\frac{50}{30}-\frac{45}{30}\right)-\left(\frac{18}{6}-\frac{14}{6}+\frac{15}{6}\right)\)
\(A=\frac{35}{6}-\frac{155}{30}-\frac{19}{6}\)
\(A=\frac{175}{30}-\frac{155}{30}-\frac{95}{30}\)
\(A=-\frac{5}{2}\)
Thực hiện phép tính ( bằng cách hợp lí nếu có thể )
A. 2/3 - (- 1/4)+3/5-(+7/45)-(-5/9)+1/12+1/39
B. 6.(-2/3)^2 - 3(-2/3)^2 - 2 : (-3/2)+4
Cách 1 :
\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=\frac{35}{6}-\frac{31}{6}-\frac{19}{6}\)
\(=\frac{35-31-19}{6}=-\frac{5}{2}\)
Cách 2 :
\(A=\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)
\(=\left(6-5-3\right)+\left(-\frac{2}{3}-\frac{5}{3}+\frac{7}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=\left(-2\right)+0+\left(-\frac{1}{2}\right)=-\frac{5}{2}\)