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a) C1:
7/11 : 3/5 + 4/11 : 3/5 = 7/11 x 5/3 + 4/11 x 5/3
= (7/11 + 4/11) x 5/3
= 1 x 5/3
= 5/3
C2:
7/11 : 3/5 + 4/11 : 3/5 = (7/11 + 4/11) : 3/5
= 1 : 3/5
= 1 x 5/3
= 5/3
b) C1:
(6,24 + 1,26) : 0,75 = 7,5 : 0,75
= 10
C2:
(6,24 + 1,26) : 0,75 = 6,24 : 0,75 + 1,26 : 0,75
= 8,32 + 1,68
= 10
Cách 1
A)(7/11*4/11)*5/3=1*5/3
Cách 2 (7/11*4/11):3/5=1:3/5=5/3
Cách 1
B)7,5:0,75=10
Cách 2
6,24:0,75+1,26:0,75=8,32+1,68
Lời giải bài toán 4/164
a, cách 1 : 7/11 : 3/5 + 4/11 : 3/5 b, cách 1 : [ 6,24 + 1,26 ] : 0,75
=[ 7/11 + 4/11 ] : 3/5 = 7,5 : 0,75
= 1 : 3/5 = 10
= 5/3 cách 2 : [ 6,24 + 1,26 ] : 0,75
cách 2 :7/11 : 3/5 + 4/11 : 3/5 = 6,24 : 0,75 + 1,26 : 0,75
=35/33 + 20/33 = 8,32 + 1,68
=55/33 = 10
=5/3
\(\frac{7}{11}:\frac{3}{5}+\frac{4}{11}:\frac{3}{5}\)
= ( \(\frac{7}{11}+\frac{4}{11}\)) : \(\frac{3}{5}\)
= 1 : \(\frac{3}{5}\)
= \(\frac{5}{3}\)
\(a.\left(\frac{7}{11}+\frac{4}{11}\right):\frac{3}{5}=1.\frac{5}{3}=\frac{5}{3}\)cách 1
\(\left(\frac{7}{11}:\frac{3}{5}\right)+\left(\frac{4}{11}:\frac{3}{5}\right)=\frac{35}{33}+\frac{20}{33}=\frac{5}{3}\)cách 2
\(b.\left(6,24+1,26\right):0,75=7,5:0,75=10\)cách 1
\(\left(6,24:0,75\right)+\left(1,26:0,75\right)=8,32+1,68=10\)cách2
7/11:3/5+4/11:3/5
=(7/11+4/11):3/5
=1:3/5
=1x5/3
=\(\frac{5}{3}\)
(6,24+1,26);0,75
=7,5:0,75
=10
a:
C1: \(\dfrac{7}{11}:\dfrac{3}{5}+\dfrac{4}{11}:\dfrac{3}{5}\)
\(=\dfrac{7}{11}\times\dfrac{5}{3}+\dfrac{4}{11}\times\dfrac{5}{3}\)
\(=\dfrac{5}{3}\left(\dfrac{7}{11}+\dfrac{4}{11}\right)=\dfrac{5}{3}\)
C2: \(\dfrac{7}{11}:\dfrac{3}{5}+\dfrac{4}{11}:\dfrac{3}{5}\)
\(=\dfrac{7}{11}\times\dfrac{5}{3}+\dfrac{4}{11}\times\dfrac{5}{3}\)
\(=\dfrac{35}{33}+\dfrac{20}{33}=\dfrac{55}{33}=\dfrac{5}{3}\)
b: C1: \(\left(6,24+1,26\right):0,75\)
\(=7,5:0,75\)
=10
C2: \(\left(6,24+1,26\right):0,75\)
=6,24:0,75+1,26:0,75
=8,32+1,68
=10