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a)\(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)
\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{1}{3}\right)+3\)
\(=1+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)
\(=1+\frac{7}{9}+3\)
\(=1+3+\frac{7}{9}\)
\(=4\frac{7}{9}\)
\(=\frac{43}{9}\)
b)\(\frac{8}{5}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{2}{5}-1\)
\(=\frac{4}{7}\cdot\left(\frac{8}{5}+\frac{2}{5}\right)-1\)
\(=\frac{4}{7}\cdot2-1\)
\(=\frac{8}{7}-1\)
\(=\frac{1}{7}\)
a) \(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)
\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)
\(=1+\frac{7}{9}+3=4\frac{7}{9}\)
b)\(\frac{8}{5}.\frac{4}{7}+\frac{4}{7}.\frac{2}{5}-1\)
\(=\frac{4}{7}.\left(\frac{8}{5}+\frac{2}{5}\right)-1\)
\(=\frac{4}{7}.2-1\)
\(=\frac{8}{7}-\frac{7}{7}=\frac{1}{7}\)
a) \(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\)
\(\frac{24}{x}=\frac{8}{5}\)
\(x=\frac{24.5}{8}\)
\(x=15\)
b) \(2.x=24\frac{1}{4}-3\frac{1}{2}\)
\(2.x=\frac{83}{4}\)
\(x=\frac{83}{8}\)
Câu c, d làm tương tự, đơn giản
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\(\frac{1}{2}\)x \(\frac{9}{10}\)+ \(\frac{8}{10}\)+ \(\frac{2}{4}\)+ \(\frac{3}{10}\)x \(0,5\)
= \(0,5\)x \(0,9\)+ \(0,8\)+ \(0,5\)x \(0,5\)
\(=0,45\)x \(1,3\)x \(0,5\)
\(=0,45\)x \(0,65=0,2925\)
\(=14:\left(\frac{14}{3}-\frac{14}{9}\right)+14:\left(\frac{2}{3}+\frac{8}{9}\right)\)
\(=14:\frac{28}{9}+14:\frac{14}{9}\)
\(=\frac{28}{9}+\frac{14}{9}\)
\(=\frac{42}{9}\)
\(14:\left(\frac{14}{3}-\frac{14}{9}\right)+14:\left(\frac{2}{3}+\frac{8}{9}\right)\)
\(=14:\left(\frac{42}{9}-\frac{14}{9}\right)+14:\left(\frac{6}{9}+\frac{8}{9}\right)\)
\(=14:\frac{28}{9}+14:\frac{14}{9}\)
\(=14.\frac{9}{28}+14.\frac{9}{14}\)
\(=14.\left(\frac{9}{28}+\frac{9}{14}\right)\)
\(=14.\left(\frac{9}{28}+\frac{18}{28}\right)\)
\(=14.\frac{27}{28}\)
\(=\frac{378}{28}\)
\(=\frac{27}{2}\)