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1) \(=\left(\frac{3}{5}+\frac{2}{5}\right).\frac{6}{11}\)
\(=1.\frac{6}{11}\)
\(=\frac{6}{11}\)
2)\(\frac{17}{25}.\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\)
\(=\frac{17}{25}.1\)
\(=\frac{17}{25}\)
Bài 1:
Rút gọn các phân số sau:
\(\dfrac{12}{24}\) = \(\dfrac{12:12}{24:12}\) = \(\dfrac{1}{2}\)
\(\dfrac{120}{90}\) = \(\dfrac{120:30}{90:30}\) = \(\dfrac{4}{3}\)
\(\dfrac{42}{24}\) = \(\dfrac{42:6}{24:6}\) = \(\dfrac{7}{4}\)
Bài 2:
Tính bằng cách thuận tiện:
\(\dfrac{13}{19}\) + \(\dfrac{18}{19}\) + \(\dfrac{17}{19}\)
= \(\dfrac{13+18+17}{19}\)
= \(\dfrac{\left(13+17\right)+18}{19}\)
= \(\dfrac{48}{19}\)
\(\dfrac{12}{17}\) + \(\dfrac{19}{17}\) + \(\dfrac{8}{17}\)
= \(\dfrac{12+19+8}{17}\)
= \(\dfrac{\left(12+8\right)+19}{17}\)
= \(\dfrac{39}{17}\)
TL :
Có số số hạng là : 39 - 30 : 1 + 1 = 10
Có số cặp là : 10 : 2 = 5
Tổng 1 cặp là : 30 + 39 = 69
Tổng dẵy số là : 69 x 5 = 345
T I C K cho tui !
~HT~
b) MSC=30492
11/12=27951/30492
19/21=27588/30492
115/121=28980/30492
kinh khủng
Bài 1:
\(\dfrac{2}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{2}{5}\)
=\(\dfrac{40}{60}\) + \(\dfrac{45}{60}\) - \(\dfrac{24}{60}\)
= \(\dfrac{61}{60}\)
b; \(\dfrac{12}{13}\) x \(\dfrac{3}{4}\) - \(\dfrac{7}{13}\)
= \(\dfrac{9}{13}\) - \(\dfrac{7}{13}\)
= \(\dfrac{2}{13}\)
c; \(\dfrac{15}{17}\) : \(\dfrac{19}{34}\) - \(\dfrac{17}{19}\)
= \(\dfrac{15}{17}\) x \(\dfrac{34}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{30}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{13}{19}\)
Bài 2:
a; \(\dfrac{x}{5}\) x \(\dfrac{3}{7}\) = \(\dfrac{9}{35}\)
\(\dfrac{x}{5}\) = \(\dfrac{9}{35}\) : \(\dfrac{3}{7}\)
\(\dfrac{x}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) x 5
\(x\) = 3
\(\dfrac{14}{17}:\dfrac{17}{32}-\dfrac{14}{17}:\dfrac{17}{15}\\ =\dfrac{14}{17}\times\dfrac{32}{17}-\dfrac{14}{17}\times\dfrac{15}{17}\\ =\dfrac{14}{17}\times\left(\dfrac{32}{17}-\dfrac{15}{17}\right)\\ =\dfrac{14}{17}\times\dfrac{17}{17}\\ =\dfrac{14}{17}\times1\\ =\dfrac{14}{17}\)
\(\Rightarrow\dfrac{14}{17}\times\dfrac{32}{17}-\dfrac{14}{17}\times\dfrac{15}{17}=\dfrac{14}{17}\times\left(\dfrac{32}{17}-\dfrac{15}{17}\right)=\dfrac{14}{17}\times\dfrac{17}{17}=\dfrac{14}{17}\)