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Cần nhớ:
\(\frac{a}{b}< 1\Rightarrow\frac{a}{b}< \frac{a+n}{b+n}\left(n\inℕ^∗\right)\)
\(\frac{a}{b}>1\Rightarrow\frac{a}{b}>\frac{a+n}{b+n}\left(n\inℕ^∗\right)\)
Ta thấy:
\(\frac{19}{29}< 1\Rightarrow\frac{19}{29}< \frac{19+1}{29+1}=\frac{20}{30}=\frac{2}{3}\)
Ta lại có:
\(\frac{2}{3}=\frac{2.7}{3.7}=\frac{14}{21}< 1\Rightarrow\frac{14}{21}< \frac{14+6}{21+6}=\frac{20}{27}=\frac{20.3}{27.3}=\frac{60}{81}\)
\(\Rightarrow\frac{19}{29}< \frac{60}{81}\) (1)
Ta có:
\(\frac{60}{81}=\frac{20}{27}< 1\Rightarrow\frac{20}{27}< \frac{20+1}{27+1}=\frac{21}{28}< \frac{21}{25}\)
=>\(\frac{60}{81}< \frac{21}{25}\) (2)
Từ (1) và (2) => \(\frac{19}{29}< \frac{60}{81}< \frac{21}{25}\)
\(\frac{21}{25}=\frac{49329}{58725}\)
\(\frac{60}{81}=\frac{43500}{58725}\)
\(\frac{19}{29}=\frac{38475}{58725}\)
\(\)vì \(\frac{49329}{58725}>\frac{43500}{58725}>\frac{38475}{58725}\)nên\(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)
\(\frac{21}{25};\frac{60}{81};\frac{19}{29}\)
Ta có : \(\frac{60}{81}=\frac{60:3}{81:3}=\frac{20}{27}\); giữ nguyên \(\frac{21}{25};\frac{19}{29}\).
Vì \(\frac{21}{25}>\frac{20}{25}>\frac{20}{27}\)nên \(\frac{21}{25}>\frac{20}{27}\)
Vì \(\frac{20}{27}>\frac{20}{29}>\frac{19}{29}\)nên \(\frac{20}{27}>\frac{19}{29}\). Vậy :
\(\frac{21}{25}>\frac{20}{27}>\frac{19}{29}\)hay \(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)
a) \(\frac{3}{5}\times\frac{8}{27}\times\frac{5}{3}\)
\(=\left(\frac{3}{5}\times\frac{5}{3}\right)\times\frac{8}{27}\)
\(=1\times\frac{8}{27}\)
\(=\frac{8}{27}\)
b) \(\frac{7}{19}\times\frac{1}{3}+\frac{7}{19}\times\frac{2}{3}\)
\(=\frac{7}{19}\times\left(\frac{1}{3}+\frac{2}{3}\right)\)
\(=\frac{7}{19}\times1\)
\(=\frac{7}{19}\)
1/ 2016 x 7 - 7 x 2015
= 7 x (2016 - 2015)
= 7 x 1
= 7
2/ \(\frac{5}{13}\times\frac{26}{25}+\frac{3}{5}\)
\(=\frac{5\times26}{13\times25}+\frac{3}{5}\)
\(=\frac{5\times2\times13}{13\times5\times5}+\frac{3}{5}\)
\(=\frac{2}{5}+\frac{3}{5}\)
\(=1\)
Ủng hộ mk nha ^_-
a)4,25+3,15+3,75+5,85=(4,25+3,75)+(3,15+5,85)=8+9=17.
b)(3/5+4/7)+2/5=(3/5+2/5)+4/7=1+4/7=11/7.
c)6,24+5,36+3,76=(6,24+3,76)+5,36=10+5,36=15,36.
d)(19/15+3/5)+11/15=(19/15+11/15)+3/5=2+3/5=13/5.
ủng hộ nha có j kb vs mk
Tính bằng cách thuận tiện nhất:
a ) 4,25 + 3,15 + 3,75 + 5,85
= ( 4,25 + 3,75 ) + ( 3,15 + 5, 85 )
= 8 + 9
= 17
tks giúp mk vs ạ!
ta có: \(1-\frac{17}{20}=\frac{3}{20};1-\frac{22}{25}=\frac{3}{25}\)
\(\Rightarrow\frac{3}{20}>\frac{3}{25}\Rightarrow1-\frac{17}{20}>1-\frac{22}{25}\)
\(\Rightarrow\frac{17}{20}< \frac{22}{25}\)
a)=384:(25*4)=384:100=3,84.
b)37/25:5/4:74/25=37/25*4/5*25/74=37*4*25/5*25*74=2/5.
c)380:(38*2)=(380:38):2=10:2=5.
d)6/11:4/3:5/11:4/3=6/11*3/4*11/5*3/4=6*3*11*3/11*4*5*4=27/40.
k nha
#)Giải :
1.
Ta có : \(\frac{n+1}{n+2}>\frac{n}{n+2}>\frac{n}{n+3}\)
\(\Rightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)
2.
a) \(x\left(104,5-14,1+9,6\right)=25\)
\(x\times100=25\)
\(x=25\div100\)
\(x=0,25\)
Bài 1 : Ta có :\(\frac{n+1}{n+2}>\frac{n}{n+2}>\frac{n}{n+3}\)
\(\Leftrightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)
Bài 2 : \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(\Leftrightarrow\left[104,5-14,1+9,6\right]\cdot x=25\)
\(\Leftrightarrow100\cdot x=25\)
\(\Leftrightarrow x=\frac{1}{4}\)
\(1+2+3+4+...+x=210\)
Số số hạng của dãy là : \((x-1):1+1=x\) số
Cho nên tổng của dãy đó là : \(\frac{x(x+1)}{2}=210\)
\(\Leftrightarrow x(x+1)=420\)
\(\Leftrightarrow x(x+1)=20\cdot21\)
\(\Leftrightarrow x=20\)
\(x-\frac{3}{4}=1-\frac{5}{6}\)
\(\Leftrightarrow x-\frac{3}{4}=\frac{1}{6}\)
\(\Leftrightarrow x=\frac{1}{6}+\frac{3}{4}=\frac{11}{12}\)
a)(33,76+6,24)+19,52
=40+19,52
=59,52
b) (\(\frac{38}{11}\)+\(\frac{6}{11}\)) +\(\frac{13}{16}\)
=4+\(\frac{13}{16}\)
=\(\frac{77}{16}\)