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DD
0
PP
0
1 tháng 10 2018
trả lời :
\(\frac{5^9.16^2}{10^4.4^3}=\frac{5^9.\left(2^4\right)^2}{2^4.5^4.\left(2^2\right)^3}=\frac{5^9.2^8}{2^{10}.5^4}=\frac{5^5}{2^2}=\frac{3125}{4}\)
D
18 tháng 5 2016
1.a) \(\left(\frac{3}{5}\right)^{15}:\left(\frac{9}{25}\right)^5=\frac{3^{15}}{5^{15}}.\frac{5^{10}}{3^{10}}=\frac{3^5}{5^5}=\left(\frac{3}{5}\right)^5\)
b)\(\left(\frac{2}{3}\right)^{10}:\left(\frac{4}{9}\right)^4=\frac{2^{10}}{3^{10}}.\frac{3^8}{2^8}=\frac{2^2}{3^2}=\left(\frac{2}{3}\right)^2\)
2.
a)\(2^x=4\Rightarrow2^x=2^2\Rightarrow x=2\)
b)\(x^3=-27\Rightarrow x^3=-3^3\Rightarrow x=-3\)
c)\(x^2=16\Rightarrow x=\pm4\)
d)\(\left(x+1\right)^2=9\Rightarrow\hept{\begin{cases}x+1=3\Rightarrow x=2\\x+1=-3\Rightarrow x=-4\end{cases}}\)
DH
25 tháng 6 2017
a, \(\dfrac{4^2.4^3}{2^{10}}=\dfrac{4^5}{2^{10}}=\dfrac{\left(2^2\right)^5}{2^{10}}=\dfrac{2^{10}}{2^{10}}=1\)
b, \(\dfrac{2^7.9^3}{6^5.8^2}=\dfrac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\dfrac{2^7.3^6}{2^5.3^5.2^6}=\dfrac{3}{2^4}=\dfrac{3}{16}\)
c, \(\dfrac{9^7.5^6.125^9}{15^{15}.5^{18}}=\dfrac{3^{21}.5^6.5^{27}}{5^{15}.3^{15}.5^{18}}=\dfrac{3^{21}.5^{33}}{3^{15}.5^{33}}=3^6=729\)
d, \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^9.\left(1+3.5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}=\dfrac{2.16}{3^2.5}=\dfrac{32}{45}\)
Chúc bạn học tốt!!!
30 tháng 7 2018
1. \(\frac{125^{10}.8^{30}}{5^{29}.2^{60}}\) = \(\frac{5^{30}.2^{90}}{5^{29}.2^{60}}\) = ............
Kl ............
LT
0
Q
10 tháng 6 2017
\(\dfrac{8^5\cdot\left(-5\right)^8+\left(-2\right)^5\cdot10^9}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{2^{15}\cdot5^8-2^5\cdot10^9}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(2^{10}\cdot5^{18}-10^9\right)\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(2^2\cdot10^8-10^9\right)\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(2^2-10\right)\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{\left(4-10\right)\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-6\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-3\cdot2\cdot10^8\cdot2^5}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-3\cdot2^6\cdot10^8}{2^{16}\cdot5^7+20^8}\)
\(=\dfrac{-3\cdot64\cdot10^8}{2^{16}\cdot5^7+20^8}\)
10 tháng 6 2017
\(\dfrac{8^5.\left(-5\right)^8+\left(-2\right)^5.10^9}{2^{16}.5^7+20^8}=\dfrac{\left(2^3\right)^5.5^8+\left(-2\right).2^4.2^9.5^9}{2^{16}.5^7+\left(2^2\right)^8.5^8}\) \(=-\dfrac{2^{15}.5^8+2^{14}.5^9}{2^{16}.5^7+2^{16}.5^8}=-\dfrac{2^{14}.5^8.\left(2+5\right)}{2^{16}.5^7.\left(1+5\right)}=-\dfrac{5.7}{4.6}=-\dfrac{35}{24}\)