TD
1
K
Khách
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VP
2
14 tháng 3 2018
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
học tốt ~~~
14 tháng 3 2018
\(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}\\ =2\)
LL
1
27 tháng 8 2023
\(\dfrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\) (sửa \(-9^9\rightarrow.9^9\))
\(=\dfrac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(=\dfrac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\dfrac{2^{29}.3^{18}\left(15-9\right)}{2^{28}.3^{18}\left(15-14\right)}\)
\(=2.6=12\)
LT
0
SS
1
PA
25 tháng 7 2016
\(\frac{5\times4^{15}\times9^9-4\times3^{20}\times8^9}{5\times2^9\times6^{19}-7\times2^{29}\times27^6}\)
\(=\frac{5\times\left(2^2\right)^{15}\times\left(3^2\right)^9-2^2\times3^{20}\times\left(2^3\right)^9}{5\times2^9\times\left(2\times3\right)^{19}-7\times2^{29}\times\left(3^3\right)^6}\)
\(=\frac{5\times2^{30}\times3^{18}-2^2\times3^{20}\times3^{27}}{5\times2^9\times2^{19}\times3^{19}-7\times2^{29}\times3^{18}}\)
\(=\frac{2^{29}\times3^{18}\times\left(5\times2-3^2\right)}{2^{28}\times3^{18}\times\left(5\times3-7\times2\right)}\)
\(=2\)
Chúc bạn học tốt ^^
BT
1
AH
Akai Haruma
Giáo viên
21 tháng 8
Lời giải:
\(\frac{5.(2^2)^{15}.(3^2)^9-2^2.3^{20}.(2^3)^9}{5.2^9.2^{19}.3^{19}-7.2^{29}.(3^3)^6}\\
=\frac{5.2^{30}.3^{18}-3^{20}.2^{29}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\\
=\frac{2^{29}.3^{18}(2.5-3^2)}{2^{28}.3^{18}(5.3-7.2)}=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)
TD
2
1 tháng 3 2015
\(A=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2.2^{29}.3^{18}-2^{29}.3^2.3^{18}}{5.2^{28}.3.3^{18}-7.2.2^{28}.3^{18}}=\frac{\left(5.2-3^2\right).2^{29}.3^{18}}{\left(5.3-7.2\right).2^{28}.3^{18}}\)
\(=2\)
TD
6
AO
9 tháng 2 2018
\(A=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(A=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(A=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(A=\frac{2.\left(10-9\right)}{15-14}\)
\(A=2\)
vậy \(A=2\)
9 tháng 4 2019
\(A=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(A=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(A=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(A=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(A=\frac{2.\left(10-9\right)}{15-14}\)
\(A=2\)
\(VậyA=2\)
BM
0
DA
1
XO
24 tháng 7 2020
Ta có : \(\frac{5.4^{15}.9^9+4.3^{20}.\left(-8\right)^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)
CV
1
3 tháng 6 2018
Xét tử :
5.415.99 - 4.320.89
= 5.230.318 - 22 . 320 . 227
= 5 . 230 . 318 - 229 . 320
= 318 . 220 . ( 5 . 210 - 29 . 32 )
= 318 . 220 . [ 29 . ( 5 . 2 - 32 ) ]
= 318 . 220 . 29
= 318 . 229
Xét mẫu :
5.29.619 - 7.229.276
= 5 . 29 . 219 . 319 - 7 . 229 . 318
= 5 . 228 . 319 - 7 . 229 . 318
= 318 . 228 . ( 5 . 3 - 7 . 2 )
= 318 . 228
B = \(\frac{3^{18}.2^{29}}{3^{18}.2^{28}}=2\)
Lời giải:
\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\\ =\frac{5.2^{30}.3^{18}-3^{20}.2^{29}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\\ =\frac{2^{29}.3^{18}(5.2-3^2)}{2^{28}.3^{18}(5.3-7.2)}=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)