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a, 32 . 5 - 2x . 6 + 183
= 9 . 5 - 2x . 6 + 1
= 45 - 2x . 6 + 1
= 45 - 2x + 1 . 3 + 1
= 3( 15 - 2x + 1) + 1
b, 100 : { 280 : [ 450 - ( 480 - 4 . 52 ) ] }
= 100 : { 280 : [ 450 - 380 ] }
= 100 : { 280 : 70 }
= 100 : 4 = 25
c, 8 . { 24 - [ 3 . ( 5 + 25 ) + 15 ] : 15 }
= 8 . { 24 - [ 3 . 30 + 15 ] : 15 }
= 8 . { 24 - 105 : 15 }
= 8 . { 24 - 7 }
= 8 . 17 = 136
a: \(A=\dfrac{16^5\cdot15^5}{2^{10}\cdot3^5\cdot5^4}=\dfrac{2^{20}\cdot3^5\cdot5^5}{2^{10}\cdot3^5\cdot5^4}=2^{10}\cdot5=5120\)
b: \(B=\dfrac{2^{15}\cdot3+2^{19}\cdot10}{2^{12}\cdot26}=\dfrac{2^{15}\left(3+2^4\cdot10\right)}{2^{13}\cdot13}=2^2\cdot\dfrac{163}{13}=\dfrac{652}{13}\)
a, 8*17*125=(8*125)*17=1000*17=17000
b, 4*37*25=(4*25)*37=100*37=3700
a: \(\left(2x-3\right)\cdot12=6^2\)
\(\Leftrightarrow2x-3=3\)
hay x=3
(0.6)^5/(0.2)^6
= [(0.2)^5. 3^5]/(0.2)^6
= 3^5/0.2
=243/0.2
= 1215
6^3+3.6^2+3^3/-13
= 2^3.3^3+3.2^2.3^2+3^3/-13
=3^3(2^3+2^2+1)/-13
=3^3.13/-13
=-27
\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{\left(3\cdot2\right)^3+3\cdot\left(3\cdot2\right)^2+3^3}{-13}=\frac{3^3\cdot2^3+3\cdot3^2\cdot2^2+3^3}{-13}=\frac{3^3\cdot\left(2^3+2^2+1\right)}{-13}=\frac{27\cdot13}{-13}=-27\)
A=\(\dfrac{9^5.30^3}{3^{15}.5^3.6^2}=\dfrac{3^{10}.3^3.10^3}{3^{15}.5^3.2^2.3^2}=\dfrac{3^{13}.2^3.5^3}{3^{15}.5^3.2^2.3^2}=\dfrac{2}{3^4}=\dfrac{2}{81}\)
a; 23.6 - (15 + 58 : 56)
= 8.6 - (15 + 52)
= 48 - (15+ 25)
= 48 - 40
= 8
b; 32.64 + 36.32 - 450
= 9.64 + 36.9 - 9.50
= 9.(64 + 36 - 50)
= 9.(100 - 50)
= 9.50
= 450