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\(\frac{\left(1,16-x\right).5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right).2\frac{2}{17}}=75\%\) <=> \(\frac{6,09-5,25x}{\left(\frac{95}{9}-\frac{29}{4}\right).\frac{36}{17}}=\frac{3}{4}\)<=> \(\frac{6,09-5,25x}{\frac{119}{36}.\frac{36}{17}}=\frac{3}{4}\)
<=> \(\frac{6,09-5,25x}{7}=\frac{3}{4}\)<=> 4(6,09-5,25x)=21 <=> 24,36-21x=21
=> 21x=3,36 => x=3,36:21 => x=0,16
Đáp số: x=0,16
\(\left(3\frac{1}{2}-2x\right).75\%=7\frac{1}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{75}{100}=\frac{22}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{3}{4}=\frac{22}{3}\)
\(\frac{7}{2}-2x=\frac{22}{3}:\frac{3}{4}\)
\(\frac{7}{2}-2x=\frac{22}{3}.\frac{4}{3}\)
\(\frac{7}{2}-2x=\frac{88}{9}\)
\(2x=\frac{7}{2}-\frac{88}{9}\)
\(2x=\frac{63}{18}-\frac{176}{18}\)
\(2x=\frac{-113}{18}\)
\(x=\frac{-113}{18}:2\)
\(x=\frac{-113}{36}\)
\(1)\)\(\frac{3}{4}\cdot2+\frac{5}{2}\cdot\frac{1}{3}=\frac{3}{2}+\frac{5}{6}=\frac{9+5}{6}=\frac{14}{6}=\frac{7}{3}\)
\(2)\)\(\frac{5}{2}+\frac{3}{11}\cdot\frac{7}{26}\left(19-6\right)=\frac{5}{2}+\frac{3\cdot7}{11\cdot2}=\frac{5}{2}+\frac{21}{22}==\frac{38}{11}\)
\(75\%+1,1:\left(\frac{2}{5}-1\frac{1}{2}\right)-\left(\frac{1}{3}\right)^2=\frac{3}{4}+1,1:\left(\frac{2}{5}-\frac{3}{2}\right)-\frac{1}{9}=\frac{3}{4}+1,1:\left(-\frac{11}{10}\right)-\frac{1}{9}=\)
\(=\frac{3}{4}-1,1:1,1-\frac{1}{9}=\frac{3}{4}-1-\frac{1}{9}=-\frac{13}{36}\)