Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26+12}{81}=\dfrac{38}{81}\)
\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5+56}{64}=\dfrac{61}{64}\)
\(\dfrac{26}{81}+\dfrac{4}{27}=\dfrac{26}{81}+\dfrac{4\times3}{27\times3}=\dfrac{26}{81}+\dfrac{12}{81}=\dfrac{38}{81}\)
\(\dfrac{5}{64}+\dfrac{7}{8}=\dfrac{5}{64}+\dfrac{7\times8}{8\times8}=\dfrac{5}{64}+\dfrac{56}{64}=\dfrac{61}{64}\)
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: =17/21(3/5+2/5)=17/21
Cách 1 : \(\dfrac{5}{7}\times\dfrac{3}{21}+\dfrac{2}{7}\times\dfrac{3}{21}=\dfrac{5}{49}+\dfrac{2}{49}=\dfrac{1}{7}\)
Cách 2 : \(\dfrac{5}{7}\times\dfrac{3}{21}+\dfrac{2}{7}\times\dfrac{3}{21}=\dfrac{3}{21}\times\left(\dfrac{5}{7}+\dfrac{2}{7}\right)=\dfrac{1}{7}\times1=\dfrac{1}{7}\)
CÁCH 1:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{35}+\frac{34}{105}=\frac{17}{21}\)
CÁCH 2:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{21}\times(\frac{3}{5}+\frac{2}{5})=\frac{17}{21}\times1=\frac{17}{21}\)
Cách 1:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
\(=\frac{3\times17}{5\times21}+\frac{17\times2}{21\times5}\)
\(=\frac{17}{5\times7}+\frac{34}{105}\)
\(=\frac{17}{35}+\frac{34}{105}\)
\(=\frac{17\times3}{35\times3}+\frac{34}{105}\)
\(=\frac{51+34}{105}\)
\(=\frac{85}{105}\)
\(=\frac{17}{21}\)
Cách 2:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
\(=\frac{17}{21}\times\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=\frac{17}{21}\times1\)
\(=\frac{17}{21}\)
C1 : 3/5 + 17/21 + 17/21 x 2/5
= 3/5 + 17/21 x ( 1 + 2/5 )
= 3/5 + 17/21 x ( 5/5 + 2/5 )
= 3/5 + 17/21 x 7/5
= 3/5 + 17/15
= 9/15 + 17/15
= 26/15
Ta có : 21.5 - 21 - 4.21 = 21.5 - 21.1 - 21.4 = 21(5 - 1 - 4) = 21.0 = 0
=> \(\frac{1+2+3+4+5+6+7}{21\cdot5-21-4\cdot21}=\frac{1+2+3+4+5+6+7}{0}\)
=> không thể tính được vì mẫu số phải khác 0
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: \(=\dfrac{17}{21}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{17}{21}\)
3/22 x 33/11 x 22= 3/22 x22 x 3=3 x 3=9
3/5 x 17/21 + 17/21 + 2/5= 17/21(3/5 + 2/5)= 17/21x 1=17/21
(1/2+1/3)2/5=1/2x2/5+1/3x2/5 =1/5+2/15=1/3
TL
= \(\frac{68}{21}\)
nhaaaaaaaa
HT