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\(\left(125^3.7^5-175^5:5\right):2016^{2017}\)
= \(\left[\left(5^3\right)^3.7^5-\left(5^2.7\right)^5:5\right]:2016^{2017}\)
= \(\left[5^{3.3}.7^5-5^{2.5}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^{10}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^9.7^5\right]:2016^{2017}\)
= \(0:2016^{2017}\)
= \(0\)
\(\dfrac{125^3\cdot7^5-175^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^{10}\cdot7^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^9\cdot7^5}{2016^{2017}}\)
=0
a) \(9^3\cdot3^2\)
\(=\left(3^2\right)^3\cdot3^2\)
\(=3^6\cdot3^2\)
\(=3^8\)
b) \(x^7\cdot x:x^4\)
\(=x^8:x^4\)
\(=x^4\)
c) \(7\cdot3^9+3^{10}+51\cdot3^8\)
\(=3^8\cdot\left(7\cdot3+3^2+51\right)\)
\(=3^8\cdot81\)
\(=3^8\cdot3^4\)
\(=3^{12}\)
d) \(5^{15}\cdot125^3\cdot625\)
\(=5^{15}\cdot5^9\cdot5^4\)
\(=5^{28}\)
`5^12 .25^4 .125^3 .625^2=5^12 . (5^2)^4 . (5^3)^3 . (5^4)^2 =5^12 .5^8 .5^9 .5^8=5^37`
bang 0 day ban oi
neu dung cu
Bai nay minh cung gap trong thi toan violympic ne ma khong co giai duoc buon ghe huuuuu
Bam may tinh thi ra la math erro
Ban oi sao khong co mu len gi het vay co the may ban kia doc se khong hieu dau