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Câu a :
\(\dfrac{5}{12}+\dfrac{3}{4}+\dfrac{1}{3}\\ =\dfrac{5}{12}+\dfrac{9}{12}+\dfrac{4}{12}=\dfrac{3}{2}\)
câu b :
\(\dfrac{1}{4}+\dfrac{3}{7}+\dfrac{11}{14}\\ =\dfrac{7}{28}+\dfrac{12}{28}+\dfrac{22}{28}=\dfrac{41}{28}\)
câu c :
\(\dfrac{1}{4}+\dfrac{3}{12}+\dfrac{12}{36}\\ =\dfrac{3}{12}+\dfrac{3}{12}+\dfrac{4}{12}\\ =\dfrac{10}{12}=\dfrac{5}{6}\)
a ) \(\frac{3}{4}\)+ \(\frac{1}{6}\) = \(\frac{18}{24}\)+ \(\frac{4}{24}\)= \(\frac{22}{24}\)
b ) \(\frac{11}{12}\)- \(\frac{3}{4}\)= \(\frac{11}{12}\)- \(\frac{9}{12}\)= \(\frac{2}{12}\)
c ) \(\frac{11}{12}\)- \(\frac{1}{6}\) = \(\frac{11}{12}\)- \(\frac{2}{12}\) = \(\frac{9}{12}\)
d ) \(\frac{1}{6}\)+ \(\frac{3}{4}\)= \(\frac{4}{24}\)+ \(\frac{18}{24}\) = \(\frac{22}{24}\)
Xin lỗi mình không rút gọn nha !
\(A=\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}\)
\(A=1+\frac{4}{9}+\frac{7}{11}\)
\(A==\frac{76}{33}\)
\(B=\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}\)
\(B=\frac{1}{2}+\frac{1}{2}\)
\(B=\frac{1}{4}\)
\(\frac{5}{12}+\frac{3}{4}+\frac{1}{3}\)
\(=\frac{5}{12}+\frac{9}{12}+\frac{4}{12}\)
\(=\frac{5+9+4}{12}\)
\(=\frac{18}{12}=\frac{9}{4}\)
\(\frac{1}{4}+\frac{3}{7}+\frac{11}{14}\)
\(=\frac{7}{28}+\frac{12}{28}+\frac{22}{28}\)
\(=\frac{7+12+22}{28}\)
\(=\frac{41}{28}\)
\(\frac{5}{12}\)+\(\frac{3}{4}\)+\(\frac{1}{3}\)=\(\frac{5}{12}\)+\(\frac{9}{12}\)+\(\frac{4}{12}\)=\(\frac{18}{12}\)=\(\frac{3}{2}\)
\(\frac{1}{4}\)+\(\frac{3}{7}\)+\(\frac{11}{14}\)=\(\frac{7+12+22}{28}\)=\(\frac{41}{28}\)
a: \(=\dfrac{21}{11}+\dfrac{12}{11}+\left(-\dfrac{9}{19}-\dfrac{3}{19}-\dfrac{6}{19}\right)=3-\dfrac{18}{19}=\dfrac{39}{19}\)
b: \(=\dfrac{2}{3}+\dfrac{4}{3}+\dfrac{3}{4}+\dfrac{7}{4}+\dfrac{4}{5}+\dfrac{16}{5}=2+4+\dfrac{5}{2}=6+\dfrac{5}{2}=\dfrac{17}{2}\)
câu a bằng 15/8
câu b bằng 19/6
câu c bằng 3/10
câu d bằng 27/4
a,
\(y:\dfrac{2}{5}=12\)
\(y=12\times\dfrac{2}{5}\)
\(y=\dfrac{24}{5}=4,8\)
b,
\(\dfrac{11}{10}+\dfrac{4}{5}\times\dfrac{3}{4}=\dfrac{11}{10}+\dfrac{12}{20}=\dfrac{22}{20}+\dfrac{12}{20}=\dfrac{34}{20}=\dfrac{17}{10}\)
\(=\dfrac{11}{12}\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right)=\dfrac{11}{12}\cdot1=\dfrac{11}{12}\)
\(\frac{3}{4}+\frac{1}{6}=\frac{9+2}{12}=\frac{11}{12}\)
\(\frac{11}{12}-\frac{3}{4}=\frac{11-9}{12}=\frac{2}{12}=\frac{1}{6}\)
\(\frac{11}{12}-\frac{1}{6}=\frac{11-2}{12}=\frac{9}{12}=\frac{3}{4}\)
\(\frac{1}{6}+\frac{3}{4}=\frac{2+9}{12}=\frac{11}{12}\)