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a.
x/y x 3/4 = 5/6 + 1/3
x/y x 3/4 = 7/6
x/y = 7/6 : 3/4
x/y = 14/9
b.
7/9 : x/y = 10/7 - 13/14
7/9 : x/y = 1/2
x/y = 7/9 : 1/2
x/y = 14/9
cho 1 k nha bn
a: =y x15/5=3y
b: =(4/6+14/6)+(7/13+19/13)+(17/9-8/9)
=3+2+1
=6
y \(\times\) \(\dfrac{16}{64}\) + y \(\times\) \(\dfrac{25}{100}\) + y \(\times\) \(\dfrac{1}{4}\) + y \(\times\) \(\dfrac{15}{60}\) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y \(\times\) ( \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\)) - \(\dfrac{13}{15}\) = \(\dfrac{17}{15}\)
y = \(\dfrac{17}{15}\) + \(\dfrac{13}{15}\)
y = \(\dfrac{30}{15}\)
y = 2
Cái này bằng rủ em chơi oẳn tù tì ,em ra lá còn anh ra hôn má em
Bài 2:
\(=\dfrac{28}{25}\cdot\dfrac{15}{7}\cdot5=\dfrac{75}{25}\cdot4=12\)
Bài 1:
a: \(x+\dfrac{7}{8}=\dfrac{13}{2}:4=\dfrac{13}{8}\)
nên x=13/8-7/8=6/8=3/4
b: \(x:\dfrac{5}{3}=\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18-10}{15}=\dfrac{8}{15}\)
nên \(x=\dfrac{8}{15}\cdot\dfrac{5}{3}=\dfrac{8}{9}\)
y x 3/7 = 13/15 - 2/5
y x 3/7 = 7/15
y = 7/15 : 3/7
y = 49/45
Vậy y = 49/45
\(Y\cdot\frac{3}{7}=\frac{13}{15}-\frac{2}{5}\)
=>\(Y\cdot\frac{3}{7}=\frac{7}{15}\)
=>\(Y=\frac{7}{15}:\frac{3}{7}=\frac{49}{45}\)
( dấu . là * đó)
a)\(x+\frac{15}{16}+\frac{7}{8}=\frac{15}{4}\)
\(x+\frac{29}{16}=\frac{15}{4}\)
\(x=\frac{15}{4}-\frac{29}{16}\)
\(x=\frac{31}{16}\)
b)\(x-\frac{27}{28}-\frac{9}{14}=\frac{13}{7}\)
\(x-\frac{45}{28}=\frac{13}{7}\)
\(x=\frac{13}{7}+\frac{45}{28}\)
\(x=\frac{97}{28}\)
c)\(x\times\frac{1}{5}+x+\frac{1}{6}=\frac{2}{3}\)
\(x\times\frac{1}{5}+x=\frac{2}{3}-\frac{1}{6}\)
\(x\times\left(\frac{1}{5}+1\right)=\frac{1}{2}\)
\(x\times\frac{6}{5}=\frac{1}{2}\)
\(x=\frac{1}{2}:\frac{6}{5}\)
\(x=\frac{5}{12}\)
d)\(x:14=\frac{1}{4}+\frac{2}{9}+\frac{3}{4}\)
\(x:14=\frac{11}{9}\)
\(x=\frac{11}{9}\times14\)
\(x=\frac{154}{9}\)
#H
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{2}{3}\) \(\times\) \(\dfrac{7}{6}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{14}{18}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{7}{9}\)
y = \(\dfrac{7}{9}\) : \(\dfrac{13}{15}\)
y = \(\dfrac{35}{39}\)
thử lại ta có:
\(\dfrac{35}{39}\) \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{7}{9}\)
\(\dfrac{2}{3}\) \(\times\) \(\dfrac{7}{6}\) = \(\dfrac{7}{9}\)
Vậy y = \(\dfrac{35}{39}\) là đúng