K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Các câu hỏi dưới đây có thể giống với câu hỏi trên
VL
0
HT
0
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 8 2023
c)\(\dfrac{3}{8}\times\dfrac{5}{8}+y=\dfrac{5}{4}\)
\(\dfrac{15}{64}+y=\dfrac{5}{4}\)
\(y=\dfrac{5}{4}-\dfrac{15}{64}\)
\(y=\dfrac{65}{64}\)
d, \(\dfrac{3}{8}+\dfrac{5}{8}\times y=\dfrac{5}{4}\)
\(\dfrac{5}{8}\times y=\dfrac{5}{4}-\dfrac{3}{8}\)
\(\dfrac{5}{8}\times y=\dfrac{7}{8}\)
\(y=\dfrac{7}{8}:\dfrac{5}{8}\)
\(y=\dfrac{7}{5}\)
21 tháng 8 2023
a, 3/4 x y = 3/5 + 3/10
3/4 x y = 9/10
y = 9/10 : 3/4
y = 6/5
b, 3/5 : y = 3/4 - 2/5
3/5 : y = 7/20
y = 3/5 : 7/20
y = 12/7
PP
0
H9
HT.Phong (9A5)
CTVHS
22 tháng 7 2023
a) \(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\)
\(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{25}{12}\)
\(\dfrac{1}{2}:y=\dfrac{25}{12}:\dfrac{3}{5}\)
\(\dfrac{1}{2}:y=\dfrac{125}{36}\)
\(y=\dfrac{1}{2}:\dfrac{125}{36}\)
\(y=\dfrac{18}{125}\)
b) \(\dfrac{4}{3}-\dfrac{1}{2}\times y=1\)
\(\dfrac{1}{2}\times y=\dfrac{4}{3}-1\)
\(\dfrac{1}{2}\times y=\dfrac{1}{3}\)
\(y=\dfrac{1}{3}:\dfrac{1}{2}\)
\(y=\dfrac{2}{3}\)
c) \(\dfrac{1}{4}+y:\dfrac{1}{3}=\dfrac{5}{6}\)
\(y:\dfrac{1}{3}=\dfrac{5}{6}-\dfrac{1}{4}\)
\(y:\dfrac{1}{3}=\dfrac{7}{12}\)
\(y=\dfrac{7}{12}\cdot\dfrac{1}{3}\)
\(y=\dfrac{7}{36}\)
LD
0
TN
2
29 tháng 4 2015
a) \(\frac{7}{10}-y\cdot\frac{3}{4}=\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{1}{2}\)
\(y=\frac{1}{2}:\frac{3}{4}\)
\(y=\frac{1}{2}\cdot\frac{4}{3}\)
\(y=\frac{2}{3}\)
b) \(\frac{5}{6}:\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}:\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}\cdot\frac{4}{3}\)
\(y+\frac{7}{9}=\frac{10}{9}\)
\(y=\frac{10}{9}-\frac{7}{9}\)
\(y=\frac{3}{9}=\frac{1}{3}\)
**** !
21 tháng 4 2021
a, \(\frac{7}{10}-y\times\frac{3}{4}=\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow y=\frac{1}{2}\div\frac{3}{4}\)
\(\Rightarrow y=\frac{1}{3}\)
b, \(\frac{5}{6}\div\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{5}{6}\div\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{10}{9}\)
\(\Rightarrow y=\frac{10}{9}-\frac{7}{9}\)
\(\Rightarrow y=\frac{1}{3}\)
H9
HT.Phong (9A5)
CTVHS
5 tháng 9 2023
\(y\times\dfrac{3}{4}++y:\dfrac{4}{5}=28\)
\(y\times\dfrac{3}{4}+y\times\dfrac{5}{4}=28\)
\(y\times\left(\dfrac{3}{4}+\dfrac{5}{4}\right)=28\)
\(y\times\dfrac{8}{4}=28\)
\(y\times2=28\)
\(y=\dfrac{28}{2}\)
\(y=14\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(a,2\dfrac{2}{5}:y\times1\dfrac{3}{4}=\dfrac{7}{8}\\ \dfrac{12}{5}:y\times\dfrac{7}{4}=\dfrac{7}{8}\\ \dfrac{12}{5}:y=\dfrac{7}{8}:\dfrac{7}{4}\\ \dfrac{12}{5}:y=\dfrac{1}{2}\\ y=\dfrac{12}{5}:\dfrac{1}{2}=\dfrac{24}{5}\\ b,3\dfrac{2}{5}:y:1\dfrac{1}{4}=2\dfrac{3}{5}\\ \dfrac{17}{5}:y:\dfrac{5}{4}=\dfrac{13}{5}\\ y:\dfrac{5}{4}=\dfrac{17}{5}:\dfrac{13}{5}\\ y:\dfrac{5}{4}=\dfrac{17}{13}\\ y=\dfrac{17}{13}\times\dfrac{5}{4}=\dfrac{85}{52}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
3 tháng 8 2023
\(c,\dfrac{12}{5}-2\dfrac{2}{5}\times y=1\dfrac{1}{4}\\ \dfrac{12}{5}-\dfrac{12}{5}\times y=\dfrac{5}{4}\\ \dfrac{12}{5}\times y=\dfrac{12}{5}-\dfrac{5}{4}\\ \dfrac{12}{5}\times y=\dfrac{23}{20}\\ y=\dfrac{23}{20}:\dfrac{12}{5}\\ y=\dfrac{23}{48}\)