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\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)
\(=3+\frac{35}{11}\times \frac{121}{245}\)
\(=3+\frac{11}{7}\)
\(= 3\frac{1}{7}(=\frac{22}{7})\)
\(12:y=\frac{3}{4}+\frac{4}{5}\)
\(12:y=\frac{15}{20}+\frac{16}{20}\)
\(12:y=\frac{31}{20}\)
\(y=12:\frac{31}{20}\)
\(y=12x\frac{20}{31}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}xY=1\)
\(y=1:\frac{4}{5}\)
\(y=1x\frac{5}{4}\)
\(y=\frac{5}{4}\)
\(\frac{37}{63}-y=\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{9}{63}\)
\(y=\frac{28}{63}\)
\(y=\frac{4}{9}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{30}{42}\)
\(y:\frac{3}{7}=\frac{33}{42}\)
\(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{11}{14}x\frac{3}{7}\)
\(y=\frac{33}{98}\)
\(12:y=\frac{3}{4}+\frac{4}{5}\) \(\frac{37}{63}-y=\frac{1}{7}\)
\(12:y=\frac{31}{20}\) \(y=\frac{37}{63}-\frac{1}{7}\)
\(y=12:\frac{31}{20}\) \(y=\frac{4}{9}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}\cdot y=1\) \(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y=1:\frac{4}{5}\) \(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{5}{4}\) \(y=\frac{11}{14}.\frac{3}{7}\)
\(y=\frac{33}{98}\)
a) 5/7 + y/35 = 4/5
y/35 = 4/5 - 5/7
y/35= 3/35
Vậy y=3 "
chúc bạn học tốt <3
Bài 2 :
a, \(\dfrac{y}{35}=\dfrac{4}{5}-\dfrac{5}{7}=\dfrac{28-25}{35}=\dfrac{3}{35}\Rightarrow y=3\)
b, \(y+\dfrac{4}{5}=\dfrac{4}{5}+\dfrac{15+21}{35}=\dfrac{4}{5}+\dfrac{36}{35}\Leftrightarrow y+\dfrac{4}{5}=\dfrac{28+36}{35}=\dfrac{64}{35}\)
\(\Leftrightarrow y=\dfrac{64}{35}-\dfrac{4}{5}=\dfrac{64-28}{35}=\dfrac{36}{35}\)
a) y + 3/7 x 21/9 = 5
y + 3/7 x 7/3 = 5
y + 1 = 5
y = 4
b) y x 3/5 - 1/2 = 4/5
y x 3/5 = 4/5 + 1/2
y x 3/5 = 13/10
y = 13/6
c) 9/8 - y + 2/5 = 1/4
y - 2/5 = 9 /8 - 1/4
y - 2/5 = 7/8
y = 51/40
d) y - 6/5 : 2/3 = 5/6
y - 9/5 = 5/6
y = 79/30
e) y : 7/8 + 3/4 = 7/4
y : 7/8 = 1
y = 7/8
a) 5/7 + y/35 = 4/5
y/35 = 4/5 - 5/7
y/35 = 3/35
y = 3/35 x 35
y = 3
b) y + 4/5 = 4/5 + (3/7 + 3/5)
y = 3/7 + 3/5
y = 36/35
k nhé:))
A) \(\frac{4}{5}\)x\( y\)=\(\frac{5}{7}:\frac{3}{14}=\frac{10}{3}\)
\(\Rightarrow y=\frac{10}{3}:\frac{4}{5}=\frac{10}{3}.\frac{5}{4}=\frac{25}{6}\)
B) \(\Rightarrow\frac{22}{5}:y=\frac{44}{5}:\frac{5}{2}=\frac{44}{5}.\frac{2}{5}=\frac{88}{25}\)
\(\Rightarrow y=\frac{22}{5}:\frac{88}{25}=\frac{22}{5}.\frac{25}{88}=\frac{5}{4}\)
\(y+\frac{5}{7}-\frac{2}{5}=\frac{38}{35}\)
\(y+\frac{5}{7}=\frac{38}{35}+\frac{2}{5}\)
\(y+\frac{5}{7}=\frac{52}{35}\)
\(y=\frac{52}{35}-\frac{5}{7}\)
\(y=\frac{27}{35}\)
y=3
25/35 + y/35 = 4/5
y/35 = 4/5 - 25/35
y/35 = 3/35
=> y = 3