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\(\left(x-7\right)\left(x-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\x-7=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=7\end{cases}}}\)
a) Ta có: \(x+\left(-5\right)=-\left(-7\right)\)
\(\Leftrightarrow x-5=7\)
\(\Leftrightarrow x=7+5=12\)
Vậy: x=12
b) Ta có: \(-5\cdot\left|x\right|=-30\)
\(\Leftrightarrow\left|x\right|=-30:\left(-5\right)=6\)
hay \(x\in\left\{6;-6\right\}\)
Vậy: \(x\in\left\{6;-6\right\}\)
c) Ta có: \(2x+20=-22\)
\(\Leftrightarrow2x=-22-20=-42\)
hay x=-21
Vậy: x=-21
d) Ta có: \(\left|x+2\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-6\right\}\)
a) \(x=-\dfrac{3}{5}\times\dfrac{9}{7}=-\dfrac{27}{35}\)
b) \(x\left(0,4-\dfrac{1}{5}\right)=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
a, \(x=-3,5.\dfrac{9}{7}=-\dfrac{9}{2}\)
b, \(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
Bài làm
( x - 7 )4 = ( x - 7 )6
=> 1 = ( x - 7 )2
=> ( x - 7 )2 = 12
=> x - 7 = 1
=> x = 8
Vậy x = 8
# Học tốt #
\(\left(x-7\right)^6=\left(x-7\right)^4\Rightarrow\left(x-7\right)^6-\left(x-7\right)^4=0\)
\(\Rightarrow\left(x-7\right)^4\left[\left(x-7\right)^3-1\right]=0\)
\(\Rightarrow\left(x-7\right)\left[\left(x-7\right)^3-1^3\right]=0\)
\(\Rightarrow\left(x-7\right)\left[\left(x-7\right)-1\right]\left[\left(x-7\right)^2+\left(x-7\right).1+1^2\right]=0\)
\(\Rightarrow\left(x-7\right)\left(x-8\right)\left(x^2-14x+49+x-7+1\right)=0\)
\(\Rightarrow\left(x-7\right)\left(x-8\right)\left(x^2-13x+43\right)=0\)
\(\Rightarrow\hept{\begin{cases}x=7\\x=8\\x\in\varnothing\end{cases}\Rightarrow\hept{\begin{cases}x=7\\x=8\end{cases}}}\)