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(x-1/2)*5/3=7/4-1/2
(x-1/2)*5/3=5/4
x-1/2=3/4
x = 5/4
(x+4/3)*7/4=5-7/6
(x+4/3)*7/4=23/6
x+4/3 = 46/21
x = 6/7
6/8=15/x
6*x=15*8
6*x=120
x = 20
\(\frac{6}{8}=\frac{15}{x}\)
\(\Rightarrow x=\left(15\cdot8\right):6\)
\(\Rightarrow x=20\)
\(\frac{3}{7}\cdot\left(\frac{2}{15}+\frac{1}{15}\right)=\frac{2}{15}\cdot\frac{3}{7}+\frac{1}{15}\cdot\frac{8}{7}\)
\(=\frac{3}{7}\cdot\frac{3}{15}\)
\(=\frac{3}{35}\)
\(x+\frac{15}{7}=\frac{9}{2}\)
\(x=\frac{9}{2}-\frac{15}{7}=\frac{33}{14}\)
\(x-\frac{3}{4}=\frac{7}{2}\)
\(x=\frac{7}{2}+\frac{3}{4}=\frac{17}{4}\)
\(x.\frac{7}{8}=\frac{12}{5}\)
\(x=\frac{12}{5}:\frac{7}{8}=\frac{96}{35}\)
\(\frac{5}{6}:x=\frac{4}{3}\)
\(x=\frac{5}{6}:\frac{4}{3}=\frac{5}{8}\)
- a) x=9/2-15/7=33/14
- b) x=7/2+3/4=17/4
- c) x=12/5:7/8=61/35
- d) x=5/6:4/3=5/8
- k nha
\(\frac{7}{8}:\left(x+1\right)=\frac{8}{7}\)
\(x+1=\frac{8}{7}\times\frac{7}{8}\)
\(x+1=1\)
\(x=1-1=0\)
Vậy x = 0 nha bn
\(\frac{7}{8}\):( X+ 1)= \(\frac{8}{7}\).
X+ 1= \(\frac{7}{8}\): \(\frac{8}{7}\).
X+ 1= \(\frac{49}{64}\).
X= \(\frac{49}{64}\)- 1.
X= -\(\frac{15}{64}\).
\(\frac{3}{4}\)x \(\frac{15}{7}\)+ \(\frac{6}{7}\)x \(\frac{6}{8}\)
= \(\frac{45}{28}\)+ \(\frac{9}{14}\)
= \(\frac{9}{4}\)
#Hoctot
\(\frac{3}{4}\times\frac{15}{7}+\frac{6}{7}\times\frac{6}{8}\)
\(=\frac{3}{4}\times\frac{15}{7}+\frac{6}{7}\times\frac{3}{4}\)
\(=\frac{3}{4}\times\left(\frac{15}{7}+\frac{6}{7}\right)\)
\(=\frac{3}{4}\times3\)
\(=\frac{9}{4}\)
Học tốt
\(x:\frac{1}{7}=14\)
=> \(x=14\times\frac{1}{7}\)
=> x = 2
Vậy x = 2
\(\frac{8}{x}=\frac{20}{15}\)
=> \(\frac{8}{x}=\frac{4}{3}=\frac{8}{6}\)
=> x = 6
Vậy x = 6
\(52\times\frac{x}{78}=3380\)
=> \(\frac{x}{78}=3380:52\)
=> \(\frac{x}{78}=65\)
=> x = 65 x 78
=> x = 5070
Vậy x = 5070
a) \(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}=\left(\frac{11}{15}+\frac{4}{15}\right)+\left(\frac{5}{7}+\frac{2}{7}\right)\)
\(=2\)
b) \(\frac{5}{9}\times\frac{1}{2}\times\frac{5}{9}\times\frac{6}{4}=\frac{25}{81}\times\frac{3}{4}=\frac{25}{108}\)
c) \(\frac{7}{8}\div\frac{1}{2}+\frac{9}{8}\div\frac{1}{2}=\left(\frac{7}{8}+\frac{9}{8}\right)\div\frac{1}{2}\)
\(=2\div\frac{1}{2}=4\)
d) \(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}=\left(\frac{17}{10}-\frac{7}{10}\right)+\frac{1}{2}\)
\(=1+\frac{1}{2}=\frac{3}{2}\)
a) \(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}\)
\(=\left(\frac{11}{15}+\frac{4}{15}\right)+\left(\frac{5}{7}+\frac{2}{7}\right)\)
\(=1+1\)
\(=2\)
b) \(\frac{5}{9}.\frac{1}{2}.\frac{5}{9}.\frac{6}{4}\)
\(=\left(\frac{5}{9}\right)^2\left(\frac{1}{2}.\frac{6}{4}\right)\)
\(=\frac{25}{81}.\frac{3}{4}\)
\(=\frac{25}{108}\)
c) \(\frac{7}{8}:\frac{1}{2}+\frac{9}{8}:\frac{1}{2}\)
\(=\frac{7}{8}.2+\frac{9}{8}.2\)
\(=2\left(\frac{7}{8}+\frac{9}{8}\right)\)
\(=2.\frac{16}{8}\)
\(=2.2\)
\(=4\)
d) \(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}\)
\(=\left(\frac{17}{10}-\frac{7}{10}\right)+\frac{1}{2}\)
\(=1+\frac{1}{2}\)
\(=\frac{2}{2}+\frac{1}{2}\)
\(=\frac{3}{2}\)
\(8\frac{7}{10}+2\frac{3}{4}=\frac{87}{10}+\frac{11}{4}=\frac{174}{20}+\frac{55}{20}=\frac{229}{20}\)
Bạn chỉ cần đưa về phân số xong tính bình thường. Muốn đổi từ hỗn số sang phân số, ta chỉ cần lấy phần nguyên nhân cho mẫu rồi cộng với tử là xong. Chứ bạn cứ hỏi mấy bài dễ như thế này thì k giỏi đc đâu!!!
a,
\(x+\frac{7}{15}=1\frac{1}{20}\)
\(x+\frac{7}{15}=\frac{21}{20}\)
\(x=\frac{21}{20}-\frac{7}{15}=\frac{63}{60}-\frac{28}{60}\)
\(x=\frac{35}{60}=\frac{7}{12}\)
b,
\(\left[3\frac{1}{2}-x\right]\cdot1\frac{1}{4}=\frac{15}{16}\)
\(\left[\frac{7}{2}-x\right]\cdot\frac{5}{4}=\frac{15}{16}\)
\(\frac{7}{2}-x=\frac{15}{16}:\frac{5}{4}=\frac{3}{4}\)
\(\frac{7}{2}-x=\frac{3}{4}\Rightarrow x=\frac{7}{2}-\frac{3}{4}\)
\(x=\frac{11}{4}\)
c,
\(1\frac{1}{5}x+\frac{2}{3}x=\frac{56}{125}\Leftrightarrow\frac{6}{5}x+\frac{2}{3}x=\frac{56}{125}\)
\(\frac{28}{15}x=\frac{56}{125}\Rightarrow x=\frac{6}{25}\)
d,
\(60\%x+0,4x+x:3=2\)
\(\frac{3}{5}x+\frac{2}{5}x+\frac{1}{3}x=2\)
\(\frac{4}{3}x=2\Rightarrow x=\frac{3}{2}\)
Nguyễn Anh Thiện
a)
x + \(\frac{7}{15}\) = \(1\frac{1}{20}\)
X + \(\frac{7}{15}=\frac{21}{20}\)
X \(=\frac{21}{20}-\frac{7}{15}\)
X \(=\frac{63}{60}-\frac{28}{60}=\frac{35}{60}=\frac{7}{12}\)
^^ Học tốt !
Theo đầu bài ta có:
\(\frac{x-7}{7}+\frac{x-7}{8}=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\frac{1}{7}+\left(x-7\right)\cdot\frac{1}{8}=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\left(\frac{1}{7}+\frac{1}{8}\right)=\frac{15}{56}\)
\(\Rightarrow\left(x-7\right)\cdot\frac{15}{56}=\frac{15}{56}\)
\(\Rightarrow x-7=1\)
\(\Rightarrow x=8\)