Question

[mimi linee]

Tìm x,biết:

1.\(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)

2. \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

3. \(\left|4.x\right|-\left|-13.5\right|=\left|2\frac{1}{4}\right|\)

Nhanh hộ em với ạ !!

Answer 1

[Hoàng Thảo]

làm tiếp cái trước(ấn nhầm)

\(x=\frac{5}{42}-\frac{15}{28}\) 

\(x=\frac{5.4}{6.4.7}-\frac{15.6}{4.7.6}\)

\(x=\frac{20}{168}-\frac{90}{168}\)

\(x=\frac{-70}{168}\)

\(x=\frac{-5}{12}\)

2. 

Answer 2

[Hoàng Thảo]

1.

 \(\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)

\(\frac{11}{13}-\frac{5}{42}+x=-\frac{15}{28}+\frac{11}{13}\)

\(\frac{11}{13}-\frac{11}{13}-\frac{5}{42}+\frac{15}{28}=-x\)