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\(\frac{x}{13}\times\frac{15}{26}=\frac{5}{14}\)
\(\frac{x}{13}=\frac{5}{14}\times\frac{26}{15}=\frac{13}{21}\)
\(\Rightarrow21\times x=13\times13\)
\(\Rightarrow x=169:21=\frac{169}{21}\)
Vậy, .....
\(\frac{x}{13}.\frac{15}{26}=\frac{5}{14}\)
\(\Rightarrow\frac{x}{13}=\frac{5}{14}:\frac{15}{26}\)
\(\Rightarrow\frac{x}{13}=\frac{5}{14}.\frac{26}{15}\)
\(\Rightarrow\frac{x}{13}=\frac{13}{21}\)
\(\Rightarrow x=\frac{13}{21}.13\)
\(\Rightarrow x=\frac{169}{21}\)
Vậy \(x=\frac{169}{21}\)

a/\(\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)
\(\Rightarrow1-x^2=\frac{7}{16}\)
\(\Rightarrow x^2=\frac{9}{16}\)
\(\Rightarrow x=\orbr{\begin{cases}\frac{3}{4}\\-\frac{3}{4}\end{cases}}\)
\(a,\frac{13}{11}.\frac{22}{26}-x^2=\frac{7}{16}\)
\(1-x^2=\frac{7}{16}\)
\(x^2=1-\frac{7}{16}=\frac{9}{16}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{4}\\x=-\frac{3}{4}\end{cases}}\)
\(b,x^2+-\frac{9}{25}=\frac{2}{5}.\frac{8}{5}\)
\(x^2+-\frac{9}{25}=\frac{16}{25}\)
\(x^2=\frac{16}{25}--\frac{9}{25}=1\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)
học tốt ~~~

<=> (x-5) ( x+1 -x-13) =10
<=> (x-5) (-12) =0
<=> x-5 =0
<=> x= 5
Ta có :
\(\left(x-5\right)\left(x+1\right)-\left(x-5\right)\left(x+13\right)=0\)
\(\Leftrightarrow\)\(\left(x-5\right)\left(x+1-x-13\right)\)
\(\Leftrightarrow\)\(\left(x-5\right).\left(-12\right)=0\)
\(\Leftrightarrow\)\(x-5=\frac{0}{-12}\)
\(\Leftrightarrow\)\(x-5=0\)
\(\Leftrightarrow\)\(x=5\)
Vậy \(x=5\)
Chúc bạn học tốt ~

Ta có :x/20=13x/260 ; 4/13=80/260 ; 5/13=100/260
vì 4/13<x/20 nên 8/260<13x/260 =>80<13x do đó 6 <x (1)
vì x/20<5/13 nên x/20<100/13=>13x<100 ,do đó x<8 (2)
từ (1) và (2) ta có x =7
vậy x =7
Ta có:\(\frac{4}{13}< \frac{x}{20}< \frac{5}{13}\)
\(\frac{80}{260}< \frac{13x}{260}< \frac{100}{260}\)
\(\Rightarrow80< 13x< 100\)
\(\Rightarrow\)x=7
Vậy x=7

a,|x|+3=5
\(\Leftrightarrow\left|x\right|=5-3=2\)
\(\Rightarrow x=\left\{{}\begin{matrix}2\\-2\end{matrix}\right.\)
b,|x+3|=5
\(\Rightarrow\left\{{}\begin{matrix}x+3=5\\x+3=-5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}2\\-8\end{matrix}\right.\)
c,|x-7|+13=25
<=>|x-7|=25-13=12
\(\Rightarrow\left\{{}\begin{matrix}x-7=12\\x-7=-12\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=19\\x=-5\end{matrix}\right.\)
d,\(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)=39\)
\(\Rightarrow\left\{{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=30\\x=-48\end{matrix}\right.\)
e,8-|x|=15
<=>|x|=8-15=-7
\(\Rightarrow\left\{{}\begin{matrix}x=-7\\x=7\end{matrix}\right.\)
f,6-|-3+x|=-15
\(\Leftrightarrow\left|-3+x\right|=6-\left(-15\right)=21\)
\(\Rightarrow\left\{{}\begin{matrix}-3+x=21\\-3+x=-21\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=24\\x=-18\end{matrix}\right.\)
a, |x| + 3 = 5
|x| = 5 - 3
|x| = 2
|x| = 2 hoặc |x| = -2
Vậy |x| thuộc {2; -2}
b,|x + 3| = 5
|x + 3| = 5 hoặc |x + 3| = -5
x = 5 - 3 x = (-5) - 3
x = 2 x = -8
Vậy x thuộc {2; -8}
c,|x - 7| + 13 = 25
|x - 7| = 25 - 13
|x - 7| = 12
|x - 7| = 12 hoặc |x - 7| = -12
x = 12 + 7 x = (-12) + 7
x = 19 x = -5
Vậy x thuộc {19 ; -5}

\(\Rightarrow x.\frac{3\left(\frac{1}{10}+\frac{1}{13}+\frac{1}{2012}\right)}{5\left(\frac{1}{10}+\frac{1}{13}+\frac{1}{2012}\right)}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3}{5}=\frac{5}{3}\)
\(\Rightarrow x=\frac{25}{9}\)
\(\frac{5}{13}:x-1\times\frac{1}{26}=-\frac{5}{13}\)
\(\frac{5}{13}:x-\frac{1}{26}=-\frac{5}{13}\)
\(\frac{5}{13}:x=\frac{-5}{13}+\frac{1}{26}\)
\(\frac{5}{13}:x=-\frac{9}{26}\)
\(x=\frac{5}{13}:\frac{-9}{26}\)
\(x=-\frac{10}{9}\)
Vậy x= -10/9