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a) x+2,5=3,15-0,4
x+2,5= 2,75
x= 2,75 - 2,5
x= 0,25
b)30 x( x:37)=2700
x:37= 2700:30
x:37 = 90
x= 90 x 37
x= 3330
3./x-1/=96=>/x-1/=96/3=32
Xảy ra 2 trw hợp
Th1 x-1=32=>x=32+1=33
Th2 x-1=-32=>x=-32+1=-31
Vậy x=-31 hoặc x=33
2x+42=-20=>2x=-20-42=-62=>x=-62/2=-31
7x-12=37=>7x=37+12=49=>x=49/7=7
3./x-1/=96
/x-1/ = 96:3
/x-1/ = 32
=> x - 1= 32
x = 32+ 1
x = 33
=> x= 33 hoặc x = -33
a) \(170-x+56=100\)
\(\Rightarrow170-x=44\)
\(\Rightarrow x=170-44\)
\(\Rightarrow x=126\)
b) \(55:x+92,3=97,3\)
\(\Rightarrow55:x=97,3-92,3\)
\(\Rightarrow55:x=5\)
\(\Rightarrow x=\dfrac{55}{5}=11\)
c) \(\left(7x-24\right)-13,5=305,5\)
\(\Rightarrow7x-24=319\)
\(\Rightarrow7x=343\)
\(\Rightarrow x=\dfrac{343}{7}=49\)
a) 170-x+56=100
170 - x = 100 - 56
170 - x= 44
x= 170 - 44
x= 126
b)55:x+92,3=97,3
55:x = 97,3 - 92,3
55:x=5
x=55:5
x=11
c) (7.x-24)-13,5=305,5
(7.x - 24) = 305,5 + 13,5
7.x - 24= 319
7.x= 319 + 24
7.x= 343
x= 343:7
x= 49
\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)
\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)
Vậy x = 5/19
\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)
Vậy x = 1/2 hoặc x = -6
\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
\(\Leftrightarrow\left(x-3\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
Vậy x = 7 hoặc x = -1
\(3^x+3^{x+1}=3^8.2+2.3^8.2017^0\)
\(3^x+3^x.3=3^8.2^2\)
\(3^x=3^8.2^2:3\)
\(3^x=3^7.2^2\)
3x+3x+1=38.2+2.38.201703x+3x+1=38.2+2.38.20170
3x+3x.3=38.223x+3x.3=38.22
3x=38.22:33x=38.22:3
3x=37.223x=37.22
a) \(x-\dfrac{3}{4}=6.\dfrac{3}{8}=\dfrac{9}{4}\)
\(\Rightarrow x=\dfrac{9}{4}+\dfrac{3}{4}=3\)
c) \(x+\dfrac{1}{2}.\dfrac{1}{3}=\dfrac{3}{4}\)
\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9}{12}-\dfrac{2}{12}=\dfrac{7}{12}\)
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`@` `\text {Ans}`
`\downarrow`
`2*x+3=8`
`=> 2x=8-3`
`=> 2x=5`
`=> x= 5 \div 2`
`=>`\(x=\dfrac{5}{2}\)
Vậy, `x=`\(\dfrac{5}{2}.\)
2.x+3=8
2.x=8-3
2.x=5
x=5:2
x=2.5
x=