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#) Giải :
a) 6,62 x \(x\)+ 3,38 x \(x\)= 5
( 6,62 + 3,38 ) x \(x\) = 5
10 x \(x\) = 5
\(x\) = 5 : 10
\(x\) = 0,5
b) \(x\)x 0,5 + \(\frac{1}{4}\)x \(x\)= \(\frac{4}{5}\)x 3
\(x\)x 0,5 + \(\frac{1}{4}\)x \(x\) = \(\frac{12}{5}\)
\(x\)x ( 0,5 + \(\frac{1}{4}\)) = \(\frac{12}{5}\)
\(x\)x 0,75 = \(\frac{12}{5}\)
\(x\) = \(\frac{12}{5}\): 0,75
\(x\) = 3,2
a) \(215+x=400\)
\(\Rightarrow x=400-215\)
\(\Rightarrow x=185\)
b) \(12,5-2x=\dfrac{1}{5}\)
\(\Rightarrow2x=12,5-\dfrac{1}{5}\)
\(\Rightarrow2x=\dfrac{123}{10}\)
\(\Rightarrow x=\dfrac{123}{10}:2\)
\(\Rightarrow x=\dfrac{123}{20}\)
a) 12 : x + 5 = 33
12 : x = 33 - 5
12 : x = 28
x = 12 : 28
x = 1/4
Vậy x = 1/4
b) 5*(x + 19) = 170 - 50
5*(x+19) = 120
x + 19 = 120 : 5
x + 19 = 24
x = 24 - 19
x = 5
Vậy x = 5
c) 11*(x - 6) - 11 = 4*x
11*(x-7) = 4x
11x - 77 = 4x
11x - 4x = 77
7x = 77
x = 11
Vậy x = 11
a: \(x+6\dfrac{1}{8}=8\)
=>\(x+\dfrac{49}{8}=\dfrac{64}{8}\)
=>\(x=\dfrac{64}{8}-\dfrac{49}{8}=\dfrac{15}{8}\)
b: \(\dfrac{11}{2}\cdot x=\dfrac{1}{5}:\dfrac{1}{3}\)
=>\(x\cdot\dfrac{11}{2}=\dfrac{1}{5}\cdot3=\dfrac{3}{5}\)
=>\(x=\dfrac{3}{5}:\dfrac{11}{2}=\dfrac{3}{5}\cdot\dfrac{2}{11}=\dfrac{6}{55}\)
c: \(x\cdot\dfrac{3}{5}+\dfrac{2}{5}\cdot x=\dfrac{4}{9}+\dfrac{1}{3}\)
=>\(x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{4}{9}+\dfrac{3}{9}\)
=>\(x\cdot1=\dfrac{7}{9}\)
=>\(x=\dfrac{7}{9}\)
\(6,62\times x+3,38\times x=5\)
\(\left(6,62+3,38\right)\times x=5\)
\(10\times x=5\)
\(x=5:10\)
\(x=0,5\)
a]6,62 *x+3,38*x=5 b] x*0,5+1/4*x=4/5*3
x*(6,62+3,38)=5 x*(0,5+0,25)=12/5
x*10=5 x*0,75=2,4
x=0,5. x=3,2