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1
2(\(\frac{3}{4}\)-5x)=\(\frac{4}{5}\)-3x
=> \(\frac{6}{4}-10x=\frac{4}{5}-3x\)
=>\(-10x+3x=\frac{4}{5}-\frac{6}{4}\)
=> \(x=\frac{1}{10}\)
2 .
\(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
=>\(\frac{3}{2}-1+4x=\frac{2}{3}-7x\)
=>\(11x=\frac{1}{6}\)
=>x=\(\frac{1}{66}\)
3.
\(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
=>\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)
=>\(-2x=\frac{-2}{3}\)
=>\(\frac{1}{3}\)
4. câu 4 ko hiểu bạn ơi
\(3\frac{1}{3}\div2\frac{2}{5}-1< x< 7\frac{2}{3}\cdot\frac{3}{7}+\frac{5}{7}\)
\(\frac{25}{18}-1< x< \frac{23}{7}+\frac{5}{7}\)
\(\frac{7}{18}< x< \frac{28}{7}\)
\(\frac{49}{126}< x< \frac{504}{126}\)
\(\Rightarrow x=\left(\frac{50}{126};\frac{51}{126};\frac{52}{126};......;\frac{503}{126}\right)\)
a) \(5x+\frac{1}{2}-x=\frac{2}{3}\)
\(\left(5x-x\right)+\frac{1}{2}=\frac{2}{3}\)
\(4x+\frac{1}{2}=\frac{2}{3}\)
\(4x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\)
\(x=\frac{1}{6}\div4\)
\(x=\frac{1}{24}\)
b) \(\frac{-2}{3}x+\frac{3}{7}+\frac{1}{2}x=\frac{-5}{6}\)
\(\left(\frac{-2}{3}x+\frac{1}{2}x\right)+\frac{3}{7}=\frac{-5}{6}\)
\(\frac{-1}{6}x+\frac{3}{7}=\frac{-5}{6}\)
\(\frac{-1}{6}x=\frac{-5}{6}-\frac{3}{7}\)
\(\frac{-1}{6}x=\frac{-53}{42}\)
\(x=\frac{-53}{42}\div\frac{-1}{6}=\frac{53}{7}\)