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11 tháng 10 2021
a) \(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\)
\(\Rightarrow32\left(2x+3\right)=24\left(3x-1\right)\)
\(\Rightarrow64x+96=72x-24\)
\(\Rightarrow8x=120\Rightarrow x=15\)
b) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Rightarrow17\left(13x-2\right)=76\left(2x+5\right)\)
\(\Rightarrow221x-34=152x+380\)
\(\Rightarrow69x=414\Rightarrow x=6\)
1 tháng 8 2018
a) \(5-\frac{2x}{3}=4x-\frac{1}{-5}\)
\(\frac{75-10x}{15}=\frac{60x+3}{15}\)
75 - 10x = 60x +3
72 = 70x
\(\frac{72}{70}\) = x
x =\(\frac{36}{35}\)
Vậy x = \(\frac{36}{35}\)
b) \(2x-\frac{10}{6}=\frac{-27}{5}-x\)
\(2x-\frac{5}{3}=\frac{-27}{5}-x\)
\(\frac{30x-25}{15}=\frac{-81-15}{15}\)
30x =-96+25
30x =-71
x= -71/30
Vậy x= -71/30
c) \(13x-\frac{2}{2x}+5=\frac{76}{17}\)
13x - 1/x +5 = 76/17
\(\frac{221x-17+85}{17x}=\frac{76x}{17x}\)
221x +68 = 76x
221x-76x =-68
145x =-68
x =\(\frac{-68}{145}\)
Vậy .........
DT
Dang Tung
CTVHS
15 tháng 1
a) \(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\\ =>32\left(2x+3\right)=24\left(3x-1\right)\\ =>64x+96=72x-24\\ =>72x-64x=24+96\\ =>8x=120\\ =>x=120:8\\ =>x=15\)
b) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\\=>76\left(2x+5\right)=17\left(13x-2\right)\\ =>152x+380=221x-34\\ =>221x-152x=34+380\\ =>69x=414\\ =>x=414:69\\ =>x=6\)
NV
Nguyễn Việt Lâm
Giáo viên
15 tháng 1
a.
\(\dfrac{2x+3}{24}=\dfrac{3x-1}{32}\)
\(\Leftrightarrow\dfrac{4\left(2x+3\right)}{4.24}=\dfrac{3\left(3x-1\right)}{32.3}\)
\(\Leftrightarrow\dfrac{8x+12}{96}=\dfrac{9x-3}{96}\)
\(\Leftrightarrow8x+12=9x-3\)
\(\Leftrightarrow9x-8x=12+3\)
\(\Leftrightarrow x=15\)
b.
ĐKXĐ: \(x\ne-\dfrac{5}{2}\)
\(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Leftrightarrow\dfrac{17\left(13x-2\right)}{17\left(2x+5\right)}=\dfrac{76\left(2x+5\right)}{17\left(2x+5\right)}\)
\(\Rightarrow17\left(13x-2\right)=76\left(2x+5\right)\)
\(\Leftrightarrow221x-34=152x+380\)
\(\Leftrightarrow69x=414\)
\(\Leftrightarrow x=6\)
30 tháng 9 2020
\(a,\frac{34}{5}:\frac{8}{5}=0,25:x\)
\(\frac{17}{4}=\frac{1}{4}:x\)
\(x=\frac{1}{4}:\frac{17}{4}\)
\(x=\frac{1}{17}\)
\(b,2x+\frac{3}{24}=3x-\frac{1}{32}\)
\(2x-3x=\frac{-1}{32}-\frac{1}{8}\)
\(-x=\frac{-5}{32}\)
\(x=\frac{5}{32}\)
\(13x-\frac{2}{2}x+5=\frac{76}{17}\)
\(12x=\frac{-9}{17}\)
\(x=\frac{-3}{68}\)
F
30 tháng 9 2020
a,\(\frac{34}{5}\div\frac{8}{5}=0,25\div x\)
\(\frac{17}{4}=0,25\div x\)
\(x=17\)
b,\(2x+\frac{3}{24}=3x-\frac{1}{32}\)
\(\Leftrightarrow2x-3x=-\frac{1}{32}-\frac{3}{24}\)
\(\Leftrightarrow2x-3x=-\frac{5}{32}\)
\(\Leftrightarrow-x=-\frac{5}{32}\)
\(\Leftrightarrow x=\frac{5}{32}\)
22 tháng 6 2016
\(a,\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
= \(\left(-\frac{3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
= \(\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
= \(\frac{1}{4}+\frac{1}{2}\)
= \(\frac{3}{4}\)
b)\(-\frac{7}{3}.\frac{5}{9}+\frac{4}{9}.\left(-\frac{3}{7}\right)+\frac{17}{7}\)
=\(-\frac{35}{27}+\left(-\frac{4}{21}\right)+\frac{17}{7}\)
= \(-\frac{35}{27}+\frac{47}{21}\)
= \(\frac{178}{189}\)
c) \(\frac{117}{13}-\left(\frac{2}{5}+\frac{57}{13}\right)\)
= \(\frac{117}{13}-\frac{311}{65}\)
= \(\frac{274}{65}\)
d) \(\frac{2}{3}-0,25:\frac{3}{4}+\frac{5}{8}.4\)
= \(\frac{2}{3}-\frac{1}{4}:\frac{3}{4}+\frac{5}{8}.4\)
= \(\frac{2}{3}-\frac{1}{3}+\frac{5}{2}\)
= \(\frac{1}{3}+\frac{5}{2}\)
= \(\frac{17}{6}\)
2 tháng 8 2018
\(\frac{5-2x}{3}=\frac{4x-1}{-5}\)
-5(5-2x) = 3(4x-1)
-25 + 10x = 12x - 3
10x - 12x = -3 + 25
-2x = 22
x= -11
Nhân chéo như trên rồi tự làm nha
Học tốt~
24 tháng 10 2021
Bài 2:
a: \(\left(3x-3\right)^2-\left(5x-3\right)^2=0\)
\(\Leftrightarrow\left(3x-3-5x+3\right)\left(3x-3+5x-3\right)=0\)
\(\Leftrightarrow-2x\left(8x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{3}{4}\end{matrix}\right.\)
15 tháng 7 2021
a) 6x(5x + 3) + 3x(1 – 10x) = 7
⇒ 30x2+18x+3x-30x2=7
⇒21x=7
⇒x=\(\dfrac{7}{21}\)
⇒x= \(\dfrac{1}{3}\)
15 tháng 7 2021
b) (3x – 3)(5 – 21x) + (7x + 4)(9x – 5) = 44
⇒15x-63x2-15+63x + 63x2-35x+36x-20=44
⇒79x-35=44
⇒79x=44+35
⇒79x=79
⇒x=1
a) \(3\dfrac{4}{5}:\dfrac{8}{5}=0,25:x\)
\(\Rightarrow\dfrac{19}{5}.\dfrac{5}{8}=\dfrac{x}{4}\)
\(\Rightarrow\dfrac{x}{4}=2\Rightarrow x=8\)
b) \(2x+\dfrac{3}{24}=3x-\dfrac{1}{32}\)
\(\Rightarrow x=\dfrac{1}{8}+\dfrac{1}{32}=\dfrac{5}{32}\)
c) \(\dfrac{13x-2}{2x+5}=\dfrac{76}{17}\)
\(\Rightarrow221x-34=152x+380\)
\(\Rightarrow69x=414\Rightarrow x=6\)