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a) \(\left(3\frac{1}{2}-2x\right).3\frac{1}{3}=7\frac{1}{3}\)
\(\left(\frac{7}{2}-2x\right).\frac{10}{3}=\frac{22}{3}\)
\(\frac{7}{2}-2x=\frac{11}{5}\)
\(2x=\frac{13}{10}\)
\(x=\frac{13}{20}\)
Vậy ...
b) \(\frac{4}{9}x=\frac{9}{8}-0,125\)
\(\frac{4}{9}x=1\)
\(x=\frac{9}{4}\)
Vậy...
\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)
\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)
\(x=1\div\left(-\frac{3}{5}\right)\)
\(x=-\frac{5}{3}\)
\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)
\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)
\(-\frac{4}{21}\cdot x=\frac{3}{5}\)
\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)
\(x=-\frac{63}{20}\)
\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{5}{7}\cdot x=1\)
\(x=1\div\frac{5}{7}\)
\(x=\frac{7}{5}\)
\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)
\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)
\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)
\(\frac{17}{33}\cdot x=\frac{9}{14}\)
\(x=\frac{9}{14}\div\frac{17}{33}\)
\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)
3/x-5 = -4/x+2
=> 3(x+2) = -4(x-5)
=> 3x + 6 = -4x + 20
=> 3x + 4x = 20 - 6
=> 7x - 14
=> x = 2
Bài trên dễ tự làm
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Rightarrow3\cdot(x+2)=-4\cdot(x-5)\)
\(\Rightarrow3x+6=-4x-20\)
\(\Rightarrow-4x-3x=6-20\)
\(\Rightarrow-7x=-14\Rightarrow x=2\)
\(2\frac{2}{5}+\frac{3}{5}x=\frac{3}{4}\)
\(\Rightarrow\frac{12}{5}+\frac{3}{5}x=\frac{3}{4}\)
Tự làm nốt
Mình bận một số công việc cho mk xin lỗi
\(\frac{4}{7}.x+0,125=1\frac{1}{8}+x\)
=>\(\frac{4}{7}.x+\frac{1}{8}=1+x+\frac{1}{8}\)
=>\(\frac{4}{7}.x=1+x\)
=>\(\frac{4}{7}.x-x=1\)
=>\(\left(\frac{4}{7}-1\right)x=1\)
=>\(\frac{-3}{7}.x=1\)
=>\(x=1:\frac{-3}{7}=\frac{1.7}{-3}=-\frac{7}{3}\)
1,\(\left(\frac{7}{2}-2x\right).\frac{4}{3}=\frac{22}{3}\)
\(x.\left(\frac{7}{2}-2\right)=\frac{22}{3}:\frac{4}{3}=\frac{22}{3}.\frac{3}{4}=\frac{11}{2}\)
\(x.\frac{3}{2}=\frac{11}{2}\)
\(x=\frac{11}{2}:\frac{3}{2}=\frac{11}{2}.\frac{2}{3}=\frac{11}{3}\)
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
a ) 3/4 . x = 1
=> x = 1 : 3/4
=> x = 1 . 4/3
=> x = 4/3
Vậy x = 4/3
b ) 4/7x = 9/8 - 0,125
=> 4/7x = 9/8 - 1/8
=> 4/7x = 8/8 = 1
=> x = 1 : 4/7
=> x = 1. 7/4
=> x = 7/4
Vậy x = 7/4
Chúc học giỏi
\(\frac{3}{4}x=1\)
\(x=1:\frac{3}{4}\)
\(x=\frac{4}{3}\)