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a. (5.x + 3) : 4 – 16 = 6
(5.x + 3) : 4 = 22
(5.x + 3) = 88
5.x = 85
x = 13
b. 7(23 – 3.x) : 2 – 35 = 35
7(23 – 3.x) : 2 = 70
7(23 – 3.x) = 35
7 . 3.x = 12
7.x = 4
x = 4/7
a.) (5.x + 3) : 4 – 16 = 6
=> (5.x + 3) : 4 = 22
=> 5.x + 3 = 88
=> 5x = 85
=> x = 17
b) 7(23 – 3.x) : 2 – 35 = 35
=> 7(23 – 3.x) : 2 = 70
=>7(23 – 3.x) = 140
=> 23 – 3.x = 20
=> 3x = 3
=> x = 1
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b) 35 - 5 * x = 20
- 5 * x = 20 - 35
-5 * x = -15
x = \(\frac{-15}{-5}\)
x = \(\frac{15}{5}\)
x = 3
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125-5(x-2)=35
5(x-2)=125-35
5(x-2)=90
x-2=90:5
x-2=18
x=18+2
x=20
Vậy x=20
125 - 5 (x - 2) = 35
5 ( x - 2 ) = 35 + 125
5 ( x - 2 ) = 160
x - 2 = 160 : 5
x - 2 = 32
x = 32 +2
x = 34
=> X = 34
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b) 45^2+45.55
=45.45+45.55
=45.(45+55)
=45.100=4500
TÌM X
gọi A=1+5+5^2+....+5^100
=> 5A=5+5^3+...+5^101
=>5A-A= 5^101-1
=>4A= 5^101-1
=>A= 5^101-1:4
TUI ĐANG VỘI NÊN CHỈ GIÚP ĐƯỢC ĐẾN ĐÂY. NHƯNG BÀI TUI LÀM ĐÚNG CHUẨN LUÔN ĐẤY!
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\(\frac{-25}{35}\cdot\frac{5}{6}< x< \left(-2\right)^2\Rightarrow\frac{-25}{42}< x< 4\)
\(\Rightarrow\frac{-25}{42}=-0,....\)
vậy chúng ta phải tìm các số có phần thập phân bé hơn 4
thế rồi bạn tự tính nhé
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\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\left(\frac{3}{5}\right)^2=\left(-\frac{3}{5}\right)^2\)
\(\Rightarrow x+\frac{1}{5}=\frac{3}{5}\) \(\Rightarrow x+\frac{1}{5}=-\frac{3}{5}\)
\(x=\frac{3}{5}-\frac{1}{5}\) \(x=-\frac{3}{5}-\frac{1}{5}\)
\(x=\frac{2}{5}\) \(x=\frac{-4}{5}\)
\(vậy...\)
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\(\frac{3}{35}-\left(\frac{3}{5}-x\right)=\frac{2}{7}\)
\(\Leftrightarrow\frac{3}{35}-\frac{3}{5}+x=\frac{2}{7}\)
\(\Leftrightarrow x=\frac{2}{7}-\frac{3}{35}+\frac{3}{5}\)
\(\Leftrightarrow x=\frac{10-3+21}{35}=\frac{28}{35}=\frac{4}{5}\)
(Nhớ k cho mình với nhá!)
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a) \(\left(3^2-2\right).\left(x-12+35\right)\)\(=\)\(5^2+279:5\)
\(7.\left(x-12+35\right)=80,8\)
\(x-12+35=80,8:7\)
\(x-12+35=\frac{404}{35}\)
\(x-12=\frac{404}{35}-35\)
\(x-12=\frac{-821}{35}\)
\(x=\frac{-821}{35}+12\)
\(x=\frac{-401}{35}\)
b) \(260:\left(x+4\right)\)\(=\)\(5\left(2^3+5\right)-3\left(3^2+2^2\right)\)
\(260:\left(x+4\right)=26\)
\(x+4=260:26\)
\(x+4=10\)
\(x=10-4\)
\(x=6\)
c) \(7^{x-3}=343\)
\(7^x:7^3=343\)
\(7^x=343.7^3\)
\(7^x=117649\)
vì \(117649=7^6\Rightarrow x=6\)
d) \(\left(x-3\right)^{2017}=\left(x-3\right)^{2016}\)
\(\Rightarrow\hept{\begin{cases}x-3=1\\x-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=4\\x=3\end{cases}}}\)
e) \(\left(2^3+3\right).\left(x-5\right)+14\)\(=\)\(5^2+124:2^2\)
\(\left(2^3+3\right).\left(x-5\right)+14=56\)
\(\left(2^3+3\right).\left(x-5\right)=56-14\)
\(\left(2^3+3\right).\left(x-5\right)=42\)
\(x-5=42:\left(2^3+3\right)\)
\(x-5=\frac{42}{11}\)
\(x=\frac{42}{11}+5\)
\(x=\frac{97}{11}\)
5(2-x)=35
(2-x)=35:7
(2-x)=5
x=5+2
x=7
5(2-x)=35
2-x=35:5
2-x=7
x=2-7
x=-5
vậy x= -5 tích mình nha ,mình trả lời đầu tiên đấy