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\(16:\left(\frac{3}{5}x+\frac{8}{21}+9\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{8}{21}+9=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{283}{21}\)
\(x=\frac{1415}{63}\)
Vậy ...
\(16\div\left(\frac{3}{5}\times x+8+\frac{9}{21}\right)=\frac{7}{10}\)
\(\Rightarrow\frac{3}{5}x+\frac{59}{7}=\frac{160}{7}\)
\(\Rightarrow\frac{3}{5}x=\frac{101}{7}\)
\(\Rightarrow x=\frac{35}{303}\)
~Study well~
#KSJ
\(16:\left(\frac{3}{5}.x+8+\frac{9}{21}\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{59}{7}=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{101}{7}\)
\(x=\frac{35}{303}\)
Bài 2:
a, \(\dfrac{5}{23}\) \(\times\) \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) \(\times\) \(\dfrac{9}{26}\)
= \(\dfrac{5}{23}\) \(\times\) ( \(\dfrac{17}{26}\) + \(\dfrac{9}{26}\))
= \(\dfrac{5}{23}\) \(\times\) \(\dfrac{26}{26}\)
= \(\dfrac{5}{23}\)
b, \(\dfrac{3}{4}\) \(\times\) \(\dfrac{7}{9}\) + \(\dfrac{7}{4}\) \(\times\) \(\dfrac{3}{9}\)
= \(\dfrac{7}{12}\) + \(\dfrac{7}{12}\)
= \(\dfrac{14}{12}\)
= \(\dfrac{7}{6}\)
\(a,x+\frac{3}{8}=\frac{4}{3}\)
\(x=\frac{4}{3}-\frac{3}{8}\)
\(x=\frac{23}{24}\)
\(b,x-\frac{1}{9}=\frac{7}{6}\)
\(x=\frac{7}{6}+\frac{1}{9}\)
\(x=\frac{23}{18}\)
\(c,x\times\frac{1}{9}=\frac{21}{8}\)
\(x=\frac{21}{8}:\frac{1}{9}\)
\(x=\frac{189}{8}\)
\(d,x:\frac{8}{3}=5\)
\(x=5\times\frac{8}{3}\)
\(x=\frac{40}{3}\)
Lời giải:
$=\frac{16}{21}+\frac{2}{9}-\frac{2}{21}+\frac{3}{9}$
$=(\frac{16}{21}-\frac{2}{21})+(\frac{2}{9}+\frac{3}{9})$
$=\frac{14}{21}+\frac{5}{9}=\frac{2}{3}+\frac{5}{9}=\frac{11}{9}$