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\(A,\left(a^6\right)^4.a^{12}=a^{24}.a^{12}=a^{36}\)
\(B,5^6:5^3+3^3.3^2=5^3+3^5=125+243=368\)
Tìm X
\(A,\left(x-1\right)^3=125=5^3\)
\(x-1=5\)
\(\Rightarrow x=6\)
\(B,720:\left[41-\left(2x-5\right)\right]=2^3.5=40\)
\(\Leftrightarrow41-\left(2x-5\right)=\frac{720}{40}=18\)
\(\Leftrightarrow2x-5=23\)
\(\Leftrightarrow x=\frac{28}{2}=14\)
1)\(2^3\cdot37-2^3\cdot63-10=2^3\left(37-63\right)-10=8\cdot-26-10\)=-218
2)\(2^3+2^2+2^4=2^2\left(1+2+4\right)=4\cdot7=28\)
3)\(5^3-5=5\left(5^2-1\right)=5\cdot24=120\)
4)\(3+3^2+3^4=3\left(1+3+3^3\right)=3\cdot13=39\)
5)\(x^{n+1}-x^n=x^n\left(x-1\right)\)
a) (5x - 12 ) : 4 = 318 : 315
( 5x - 12 ) : 4 = 33
( 5x - 12 ) : 4 = 27
5x - 12 = 108
5x = 120
x = 24
b) 5x3 - 102 = 35
5x3 - 100 = 35
5x3 = 135
x3 = 27
x3 = 33
=> x = 3
c) 65 - 4x+2 = 20180
65 - 4x+2 = 1
4x+2 = 64
4x+2 = 43
x + 2 = 3
=> x = 1
d) 2x+1 - 2x = 32
2x . ( 2 - 1 ) = 32
2x . 1 = 32
2x = 32
2x = 25
=> x = 5
Trả lời:
(-65)-(-37)
= (-65)+37
=-28
(-159)-280:(-7)
=(-159)-(-40)
=(-159)+40
=-119
(-12).\(3^2\)+240:\(\left(-2\right)^2\)
=-108+60
=-48
\(5.\left(-2\right)^3-36:3^2\)
=\(-40-4\)
=\(-44\)
\(128-\left[68+8.\left(35-37\right)^2\right]:\left(-4\right)\)
=\(128-\left[68+8.4\right]:\left(-4\right)\)
=\(128-\left[68+32\right]:\left(-4\right)\)
=\(128-100:\left(-4\right)\)
=\(128-\left(-25\right)\)
=\(153\)
\(-141+3^3+\left(-2\right)^2\)
=\(-141+9+4\)
=\(-132+4\)
=\(-128\)
chúc bạN HOK TỐT
1)(-65)-(-37)=-28
2)(-159)-280:(-7)
=(-159)-(-40)
=-119
3)(-12).3\(^2\)+240:(-2)\(^{^2}\)
=-108+60
=-48
4)5.(-2)\(^3\)-36:3\(^2\)
=-40-4
=-44
5) 128-[68+8.(35-37)2]:(-4)
=128-[68+8.-2\(^2\)]:(-4)
=128-[68+32]:(-4)
=128-100:(-4)
=128-(-25)
=153
6)-141+3\(^3\)+(-2)\(^2\)
=-114+4
=-110
\(\left(-65\right)-\left(-37\right)=\left(-65\right)+37=-\left(65-37\right)=-28\)
\(\left(-159\right)-280\div\left(-7\right)=\left(-159\right)-\left(-40\right)=-119\)
\(\left(-12\right).3^2+240\div\left(-2\right)^2=\left(-12\right).9+240\div4=\left(-108\right)+60=-48\)
\(5.\left(-2\right)^3-36\div3^2=5.\left(-8\right)-36\div9=\left(-40\right)-4=-44\)
\(128-\left[68+8.\left(35-37\right)^2\right]\div\left(-4\right)=128-\left[69+8\left(-2\right)^2\right]\div4\)
\(=128-\left(69+8.4\right)\div4=128-101\div4=128-25,25=102,75\)
\(\left(-141\right)+3^3+\left(-2\right)^2=\left(-141\right)+27+4=\left(-141\right)+31=-110\)
1) (X-6)x(2x - 6)=0
=> X - 6 = 0 => x = 0 + 6 = 6
=> 2x - 6 = 0 => 2x = 6 => X = 6 : 2 = 3
Vẫy x{6; 3}
2) 100:(x-7)=1
x-7 = 100:1
x-7 = 100
x = 100 + 7
x = 107
a) 28 + 2x = 35 - (-13)
=> 28 + 2x = 48
=> 2x = 48 - 28
=> 2x = 20
=> x = 20 : 2
=> x = 10
Vậy x = 10
b) 2(x - 1)2 - 5 = 45
=> 2(x - 1)2 = 45 + 5
=> 2(x - 1)2 = 50
=> (x - 1)2 = 50 : 2
=> (x - 1)2 = 25
=> (x - 1)2 = 52
=> x - 1 = 5
=> x = 5 + 1
=> x = 6
Vậy x = 6
c) 20 - 3|x + 5| = -7
=> 3|x + 5| = 20 - (-7)
=> 3|x + 5| = 27
=> |x + 5| = 27 : 3
=> |x + 5| = 9
TH1: x + 5 = 9
=> x = 9 - 5
=> x = 4
TH2: x + 5 = -9
=> x = -9 - 5
=> x = -14
Vậy x = 4 hoặc x = -14