Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\left(0,25-30\%.x\right).\frac{1}{3}-\frac{1}{4}=-5\frac{1}{6}\)
\(< =>\left(\frac{1}{4}-\frac{3x}{10}\right).\frac{1}{3}-\frac{1}{4}=-\frac{30}{6}\)
\(< =>\left(\frac{1}{4}-\frac{3x}{10}\right).\frac{1}{3}=-5+\frac{1}{4}=-\frac{19}{4}\)
\(< =>\frac{1}{4}-\frac{3x}{10}=\frac{-19}{4}.\frac{3}{1}=-\frac{57}{4}\)
\(< =>\frac{-3x}{10}=\frac{-57}{4}-\frac{1}{4}=-\frac{58}{4}\)
\(< =>-12x=-580\)
\(< =>12x=580< =>x=\frac{580}{12}=\frac{145}{3}\)
\(\left(0,25-30\%x\right).\frac{1}{3}-\frac{1}{4}=-5\frac{1}{6}\)
\(\left(\frac{1}{4}-\frac{3}{10}x\right)\frac{1}{3}-\frac{1}{4}=\frac{-31}{6}\)
\(\frac{1}{4}-\frac{3}{10}x=\left(\frac{-31}{6}+\frac{1}{4}\right)\div\frac{1}{3}\)
\(\frac{1}{4}-\frac{3}{10}x=\frac{-59}{4}\)
\(\frac{3}{10}x=\frac{1}{4}-\frac{-59}{4}\)
\(\frac{3}{10}x=15\Leftrightarrow x=50\)
a)12(x-1)=0
=>x-1=0
=>x=1
b) 3/5x-3/4=(-3)2-|-11|
3/5x-3/4=9-11=-2
3/5x=-2+3/4=-5/4
=>x=-5/4:3/5=-25/12
c)4(x-5/8)-3/4=0,25
4(x-5/8)=0,25+3/4=1
=>x-5/8=1/4
x=1/4+5/8=7/8
2) Số đó là
27:3/5=45
a; 0,2.\(\dfrac{15}{36}\) - (\(\dfrac{2}{5}\) + \(\dfrac{2}{3}\)): 1%
= \(\dfrac{1}{12}\) - \(\dfrac{16}{15}\): \(\dfrac{1}{100}\)
= \(\dfrac{1}{12}\) - \(\dfrac{320}{3}\)
= \(\dfrac{1}{12}\) - \(\dfrac{1280}{12}\)
= - \(\dfrac{1279}{12}\)
b; 75% - 1\(\dfrac{1}{2}\) + 0,5 : \(\dfrac{5}{12}\)
= 0,75 - 1,5 + 1,2
= -0,75 + 1,2
= 0,45
c; 1\(\dfrac{3}{15}.0,75-\left(\dfrac{8}{15}+0,25\right)\).\(\dfrac{24}{47}\)
= \(\dfrac{28}{15}\).0,75 - \(\dfrac{47}{60}\).\(\dfrac{24}{47}\)
= \(\dfrac{7}{5}-\dfrac{2}{5}\)
= 1
d; \(\dfrac{32}{15}\): (-1\(\dfrac{1}{5}\) + 1\(\dfrac{1}{3}\))
= \(\dfrac{32}{15}\): (-\(\dfrac{6}{5}\) + \(\dfrac{4}{3}\))
= \(\dfrac{32}{15}\): \(\dfrac{2}{15}\)
= 16
1.
a)
3/4- 3/2+1/2 . 12/5
=-3/4+6/5
=9/20
b)
8 . x-7,8 . x=25
0,2 x= 25
x=25 : 0,2
x=125
c)1/4 . 4/3 . 30. 1/2. 8/45
=8/9
đ) 9/2+ 3/4 x =27/8
3/4x= -9/8
x=-9/8 : 3/4
x=-3/2
b2:
a) 13/15 . 3/4-(8/15+1/4)
=39/60 - 47/60
= -8/60 = -2/15
a)\(x-\frac{1}{4}=\frac{5}{8}\)
\(x=\frac{5}{8}+\frac{1}{4}\)
\(x=\frac{7}{8}\)
b)\(\frac{x}{12}=\frac{-1}{24}-\frac{1}{8}\)
\(\frac{x}{12}=\frac{-1}{24}+\frac{-1}{8}\)
\(\frac{x}{12}=\frac{-1}{6}\)
\(x=\frac{-1}{6}\times12\)
\(x=-2\)
a)x-1/4=5/8
=>x=5/8+1/4
x=7/8
b) x/12=-1/24-1/8
=>x/12=-1/6
=>x=-2
c).......... Tự làm
a) 2.(x-1)=4/3
<=> (X-1)= 4/3 :2 = 2/3
<=> X= 2/3+1=5/3
b) (x-1)^2= 4
<=> X-1=2 hoặc x-1=-2
<=> X= 3 hoặc x= -1
c) 2.|x+1|=3
<=> Ix+1| = 3/2
<=> X+1= 3/2 hoặc x+1= -3/2
<=> X= 1/2 hoặc x= -5/2
a) Ta có: \(2\left(x-1\right)=\dfrac{4}{3}\)
\(\Leftrightarrow x-1=\dfrac{4}{3}:2=\dfrac{4}{6}=\dfrac{2}{3}\)
hay \(x=\dfrac{5}{3}\)
Vậy: \(x=\dfrac{5}{3}\)
b) Ta có: \(\left(x-1\right)^2=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-1\right\}\)