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135-5(x+4)=35
5(x+4)=135-35
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
135- 5(x+4)= 35
5(x+4)=135- 35
5(x+4)=100
x+4=100: 5
x+4=20
x=20-4
x=16
a) 135 - 5(x + 4) = 35
<=> 135 - 5x - 20 = 35
<=> 115 - 5x = 35
<=> 5x = 115 - 35
<=> 5x = 80
<=> x = 16
b) 25 + 3 (x - 8) = 106
=> 3 ( x - 8) = 106 - 25
=> 3 ( x - 8) = 81
=> ( x - 8) = 81: 3
=> x - 8 = 27
=> x = 27 + 8
=> x = .......
140 : ( x - 8 ) = 7
x - 8 = 140 : 7 = 20
x = 20 + 8
x = 28
* 140 : (X-8)=7
X-8=140:7
X-8=20
x=20+8
x=28
Vậy X =28
* 4(X+41)=400
X+41=400:4
X+41=100
X=100-41
X=59
Vậy x=59
*135-5(X+4)135
5(X+4)=135-35
5(X+4)=100
X+4=100:5
X+4=20
X=20-4
X=16
Vậy X = 16
c) 135 - | 9 - x | = 3
| 9 - x | = 135 - 3
| 9 - x | = 132
=> 9 - x = 132
x = 9 - 132
x = 123
hoặc 9 - x = - 132
x = 9 - ( - 132 )
x = 9 + 132
x = 141
Vậy ..................
c) 135 - | 9 - x | = 35
\(2\left(x-1\right)+3\left(x-2\right)=x-4\)
\(2x-2+3x-6=x-4\)
\(5x-8=x-4\)
\(5x-8-x+4=0\)
\(4x-4=0\)
\(4x=4\)
\(x=1\)
\(3\left(4-x\right)-2\left(x-1\right)=x+20\)
\(12-x-2x+2=x+20\)
\(14-3x=x+20\)
\(14-3x-x-20=0\)
\(-6-4x=0\)
\(4x=-6\)
\(x=-\frac{3}{2}\)
\(\left|2x+3\right|=5\)
\(\Rightarrow\orbr{\begin{cases}2x=2\\2x=-8\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-4\end{cases}}}\)
a) \(\left|x-2\right|-12=-1\)
\(\Leftrightarrow\left|x-2\right|=11\)
TH1 : \(x-2=11\)
\(\Leftrightarrow x=13\)
TH2 : \(x-2=-11\)
\(\Leftrightarrow x=-9\)
Vậy \(x\in\left\{13;-9\right\}\)
b) \(135-\left|9-x\right|=35\)
\(\Leftrightarrow\left|9-x\right|=100\)
TH1 : \(9-x=100\)
\(\Leftrightarrow x=-91\)
TH2 :\(9-x=-100\)
\(\Leftrightarrow x=109\)
Vậy \(x\in\left\{-81;109\right\}\)
c) \(\left|2x+3\right|=4\)
TH1 : \(2x+3=4\)
\(\Leftrightarrow2x=1\)
\(\Leftrightarrow x=\frac{1}{2}\)
TH2 : \(2x+3=-4\)
\(\Leftrightarrow2x=-7\)
\(\Leftrightarrow x=-\frac{7}{2}\)
Vậy \(x\in\left\{\frac{1}{2};-\frac{7}{2}\right\}\)
a) 135-5x=-25
5x = 135 - (-25)
5x = 160
x = 160 : 5
x = 32
b) (3-x)2 = 0
=> 3-x = 0
=> x = 3 - 0
=> x = 3
c) (4-x)2=1
\(\Rightarrow\orbr{\begin{cases}4-x=1\\4-x=-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=5\end{cases}}\)
a) 135-5x=-25
5x=135-(-25)
5x=160
x=160:5
x=32
Vậy x=32
b)(3-x)\(^2\)=0
\(\Rightarrow3-x=0\)
\(\Rightarrow x=3-0\)
\(\Rightarrow x=3\)
Vậy x=3
c)(4-x)\(^2\)=1
\(\Rightarrow\orbr{\begin{cases}4-x=-1\\4-x=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=4-\left(-1\right)\\x=4-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=3\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=5\\x=3\end{cases}}\)