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Xét vế trái:
Ta thấy:QLC là 2.
=>SSH là:(99-1):2+1=50(số)
=>Tổng là:(1+99).50:2=2500
Ta có:2500=(x-2)2=502=(-50)2
=>x-2=50 hoặc x-2=-50
x=52 x=-48
1 + 3 + 5 + ... + 99 = (x - 2)2
50 số
=> (1 + 99) × 50 : 2 = (x - 2)2
=> 100 × 50 : 2 = (x - 2)2
=> 2500 = (x - 2)2
=> x - 2 = 50 hoặc x - 2 = -50
=> x = 52 hoặc x = -48
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a, Số số hạng: ( 99 - 1 ) : 2 + 1 = 50 số
Tổng: ( 99 + 1 ) . 50 : 2 = 2500
=> ( x - 2 )3 = 2500
=> x ko có số nào thỏa mãn
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\(\text{1 + 3 + 5 + ... + 99 = (x - 2)}^2\)
\(\text{Số số hạng là:(99-1):2+1=50(số)}\)
\(\Rightarrow\text{(1 + 99) × 50 : 2 = (x - 2)}^2\)
\(\Rightarrow\text{100 × 50 : 2 = (x - 2)}^2\)
\(\text{ x - 2 = 50 hoặc x - 2 = -50}\)
\(\Rightarrow\text{x = 52 hoặc x = -48}\)
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a,3(x+1)+2x+5=28
\(\Rightarrow\)3x+3+2x+5=28
\(\Rightarrow\)5x+8=28
\(\Rightarrow\)5x=20
\(\Rightarrow\)x=4
b,3x-1=92
\(\Rightarrow\)3x-1=(32)2
\(\Rightarrow\)3x-1=34
\(\Rightarrow\)x-1=4
\(\Rightarrow\)x=5
c,3x+2+2.3x=99
\(\Rightarrow\)3x.9+2.3x=99
\(\Rightarrow\)11.3x=99
\(\Rightarrow\)3x=9
\(\Rightarrow\)3x=32
\(\Rightarrow\)x=2
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a ) \(3\left(x+1\right)+2x+5=28\)
=> \(3x+3+2x+5=28\)
=> \(5x+8=28\)
=> \(5x=20\)
=> \(x=4\)
B ) \(3^{x-1}=9^2\)
=> \(3^{x-1}=81\)
=> \(x=5\)
\(a,
3\left(x+1\right)+2x+5=28\)
\(\Rightarrow3x+3+2x+5=28\)
\(\Rightarrow5x+8=28\)
\(\Rightarrow5x=20\)
\(\Rightarrow x=4\)
\(b,3^{x-1}=9^2\)
\(\Rightarrow3^{x-1}=81\)
\(\Rightarrow x=5\)
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bn tải online math về nhé nó sẽ dịch cho bn
ta có 1 + 3 + 5 + .. + 99 = 2500
=> x2 = 2500
<=> x2 = 502
Vậy x = 50 hoặc -50