Question

[Lê Vũ Anh Thư]

Tìm x, y, z biết: 3(x - 1) = 2(y - 2); 4(y - 2) = 3(z - 3) và: 2x + 3y - z = 50

Answer 1

[I don't need you]

ta có: \(3\left(x-1\right)=2\left(y-2\right)\Rightarrow\frac{x-1}{2}=\frac{y-2}{3}\)

\(4\left(y-2\right)=3\left(z-3\right)\Rightarrow\frac{y-2}{3}=\frac{z-3}{4}\)

\(\Rightarrow\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=\frac{2x-2}{4}=\frac{3y-6}{9}\)

ADTCDTSBN

có: \(\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}=\frac{2x-2+3y-6-z+3}{4+9-4}\)

                                                                  \(\frac{\left(2x+3y-z\right)-\left(2+6-3\right)}{9}=\frac{50-5}{9}=\frac{45}{9}=5\)

\(\Rightarrow\frac{x-1}{2}=5\Rightarrow x-1=10\Rightarrow x=11\)

\(\frac{y-2}{3}=5\Rightarrow y-2=15\Rightarrow y=17\)

\(\frac{z-3}{4}=5\Rightarrow z-3=20\Rightarrow z=23\)

KL: x = 11; y= 17; z =23

Chúc bn học tốt !!!!

Answer 2

[Khuất Thị Kim Chi]

công chúa ori ơi cho mk hỏi, có thể làm tắt chỗ => \(\frac{x-1}{2}\)=5 ............................................................. không