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x+y+xy=11
=> x(y+1)+y=11
=> x(y+1)+y+1=12
=> (y+1)(x+1)=12=1.12;2.6;3.4;4.3;6.2;12.1
y+1 | 12 | 1 | 6 | 2 | 3 | 4 |
y | 11 | 0 | 5 | 1 | 2 | 3 |
x+1 | 1 | 12 | 2 | 6 | 4 | 3 |
x | 0 | 11 | 1 | 5 | 3 | 2 |
Kết luận | TM | TM | TM | TM | TM | TM |
Vậy: (x;y)= (11;0);(0;11);(5;1);(1;5);(2;3);(3;2)
Còn x+6=y(x-1)
Hưỡng dẫn: Đổi vế x từ x+6 sau đó trừ cả vế với 1 nhóm lại ta được hai thừa số
Sau đó lập thành tích.
a)Do x,y là STN mà xy=6=1.6=2.3
=>(x;y)={(1;6);(6;1);(2;3);(3;2)}
b)Do x,y là STN mà xy=40=1.40=2.20=4.10=8.5
=>(x;y)={(1;40);(40;1);(2;20);(20;2);(4;10);(10;4);(8;5);(5;8)}
x(y+2)+3y =6
=>x(y+3)+3y+9=15
=>x(y+3)+3(y+3)=15
=>(x+3)(y+3)=15
mả .....=......=>ta co bang sau
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