Question

[dghdgh]

Tìm x :

 x + {(x-3) - [(x+3) - (-x - 2)]} =x

 Ai nhanh mik tick nha mik đang cần gấp mong mng giúp mik

Answer 1

[Umi]

 x + {(x - 3) - [(x + 3) - (-x - 2)]} = x

=> x + {x - 3 - [x + 3 + x + 2]} = x

=> x + {x - 3 - x - 3 - x - 2} = x

=> x + x - 3 - x - 3 - x - 2 = x

=> (x - x) + (x - x) - (3 + 3 + 2) = x

=> 0 + 0 - 8 = x

=> - 8 = x

vậy x = - 8

Answer 2

[Nguyễn Mạnh Cường]

=>(x-3)-[(x+3)-(-x-2)]=0

=>(x-3)-(x+3+x+2)=0

=>x-3-2x-5=0

=>-x-8=0

=>-x=8=>x=-8