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a) (1,5 . 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125
=> (2,85 - x - 0,5) : 0,25 = 60
=> (2,85 - 0,5) - x = 60 . 0,25
=> 2,35 - x = 15
=> x = 2,35 - 15
=> x = -12,65
Vậy x = -12,65
b) \(1-\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\div2\frac{1}{6}=0\)
\(\Rightarrow\left(5\frac{2}{9}-7\frac{7}{18}+x\right)\div2\frac{1}{6}=1-0\)
\(\Rightarrow\left(\frac{47}{9}-\frac{133}{18}+x\right)\div2\frac{1}{6}=1\)
\(\Rightarrow\frac{-13}{6}+x=2\frac{1}{6}\)
\(\Rightarrow x=2\frac{1}{6}-\frac{-13}{6}\)
\(\Rightarrow x=\frac{13}{6}+\frac{13}{6}\)
\(\Rightarrow x=\frac{26}{6}\)
\(\Rightarrow x=\frac{13}{3}\)
Vậy \(x=\frac{13}{3}\)
c) \(35\left(2\frac{1}{5}-x\right)=32\)
\(\Rightarrow2\frac{1}{5}-x=32\div35\)
\(\Rightarrow\frac{11}{5}-x=\frac{32}{35}\)
\(\Rightarrow x=\frac{11}{5}-\frac{32}{35}\)
\(\Rightarrow x=\frac{9}{7}\)
Vậy \(x=\frac{9}{7}\)
d) \(\frac{4}{3}+\left(x\div2\frac{2}{3}-0,5\right).1\frac{35}{55}=0,6\)
\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{3}{5}-\frac{4}{3}\)
\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{-11}{15}\)
\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-11}{15}\div\frac{18}{11}\)
\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-121}{270}\)
\(\Rightarrow x\div\frac{8}{3}=\frac{-121}{270}+\frac{1}{2}\)
\(\Rightarrow x\div\frac{8}{3}=\frac{7}{135}\)
\(\Rightarrow x=\frac{7}{135}.\frac{8}{3}\)
\(\Rightarrow x=\frac{56}{405}\)
Vậy \(x=\frac{56}{405}\)
e) \(1\frac{1}{3}.2\frac{2}{4}\div\frac{5}{6}.1\frac{1}{11}=11-5\div x\)
\(\Rightarrow\frac{4}{3}.\frac{5}{2}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)
\(\Rightarrow\frac{10}{3}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)
\(\Rightarrow4.\frac{12}{11}=11-5\div x\)
\(\Rightarrow11-5\div x=\frac{48}{11}\)
\(\Rightarrow5\div x=11-\frac{48}{11}\)
\(\Rightarrow5\div x=\frac{73}{11}\)
\(\Rightarrow x=5\div\frac{73}{11}\)
\(\Rightarrow x=\frac{55}{73}\)
Vậy \(x=\frac{55}{73}\)
a) (1,5 * 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125
(2,85 - x - 0,5) : 0,25 = 60
(2,85 - x - 0,5) = 60 x 0,25
(2,85 - x - 0,5) = 15
2,35 - x = 15
x = 2,35 - 15
x = -12,65
\(\left(x-\frac{3}{5}\right):\left(2-0,5\right)=\frac{2}{3}\)
\(\Rightarrow\left(x-\frac{3}{5}\right):1,5=\frac{2}{3}\)
\(\Rightarrow x-\frac{3}{5}=1\)
\(\Rightarrow x=\frac{8}{5}\)
\(\left(x-\frac{3}{5}\right):\left(2-0,5\right)=\frac{2}{3}\)
\(\left(x-\frac{3}{5}\right):1,5=\frac{2}{3}\)
\(\left(x-\frac{3}{5}\right):\frac{3}{2}=\frac{2}{3}\)
\(\left(x-\frac{3}{5}\right).\frac{2}{3}=\frac{2}{3}\)
\(\left(x-\frac{3}{5}\right)=\frac{2}{3}:\frac{2}{3}\)
\(\left(x-\frac{3}{5}\right)=1\)
\(x=1+\frac{3}{5}\)
\(x=\frac{3}{5}\)
#)Trả lời :
\(a,\frac{2}{3}:\frac{5}{7}.\frac{5}{7}:\frac{2}{3}+1934\)
\(=\left(\frac{2}{3}:\frac{2}{3}\right).\left(\frac{5}{7}:\frac{5}{7}\right)+1934\)
\(=1.1+1934\)
\(=1935\)
#~Will~be~Pens~#
\(x\times2+x\times0,5=10\)
\(\Rightarrow x\times\left(2+0,5\right)=10\)
\(\Rightarrow x\times2,5=10\)
\(\Rightarrow x=10\div2,5\)
\(\Rightarrow x=4\)
Vậy x = 4
\(\frac{4}{7}+\frac{3}{7}\div x=\frac{3}{2}\)
\(\Rightarrow\frac{3}{7}\div x=\frac{3}{2}-\frac{4}{7}\)
\(\Rightarrow\frac{3}{7}\div x=\frac{21}{14}-\frac{8}{14}\)
\(\Rightarrow\frac{3}{7}\div x=\frac{13}{14}\)
\(\Rightarrow x=\frac{3}{7}\div\frac{13}{14}\)
\(\Rightarrow x=\frac{3}{7}\cdot\frac{14}{13}=\frac{6}{13}\)
Vậy x = \(\frac{6}{13}\)
x.2+x.0,5=10
=> x= . (2+0,5)=10
=>x.2,5=10
=>x= 10:2,5
=>x=4
vậy x = 4
b)
\(\frac{4}{7}\)+\(\frac{3}{7}\):x=\(\frac{3}{2}\)
=> \(\frac{3}{7}\):x= \(\frac{3}{2}\):\(\frac{4}{7}\)
=> \(\frac{3}{7}\):x=\(\frac{13}{14}\)
=> \(\frac{3}{7}\):x=\(\frac{3}{7}\):\(\frac{14}{13}\)
=> x =\(\frac{6}{13}\)
vậy x =\(\frac{6}{13}\)
hok tốt
a. \(\frac{-3}{2}-2x+\frac{3}{4}=-22\)2
=> \(-2x=-22+\frac{3}{2}-\frac{3}{4}\)
=> \(-2x=\frac{-85}{4}\)
=> \(x=\frac{-85}{4}:\left(-2\right)\)
=> \(x=\frac{85}{8}\)
b. \(\left(\frac{-2}{3}x-\frac{3}{5}\right).\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)
=> \(\left(\frac{-2}{3}x-\frac{3}{5}\right).\frac{-29}{6}=\frac{2}{5}\)
=> \(\frac{-2}{3}x-\frac{3}{5}=\frac{2}{5}:\left(\frac{-29}{6}\right)\)
=> \(\frac{-2}{3}x-\frac{3}{5}=\frac{-12}{145}\)
=> \(\frac{-2}{3}x=\frac{-12}{145}+\frac{3}{5}\)
=> \(\frac{-2}{3}x=\frac{15}{29}\)
=> x = \(\frac{15}{29}:\frac{-2}{3}\)
=> x = \(\frac{-45}{58}\)
\(a,3\frac{3}{10}+x=5\frac{3}{10}\)
\(\frac{33}{10}+x=\frac{53}{10}\)
\(x=\frac{53}{10}-\frac{33}{10}\)
\(x=2\)
\(b,4\frac{2}{9}-x=\frac{2}{9}\)
\(x=4\frac{2}{9}-\frac{2}{9}\)
\(x=4\)
kí hiệu U trong tập hợp có tác dụng gì ??????????????
hãy ví dụ một phép tính xem
giúp mình nhé mình đang cần gấp
=>(x - 0,6)*3=(x-0,5)*2
=>3*x-1,8=2*x-1
=>3*x-2*x=1,8-1
=>x=0,8
Vậy x=0,8
("Lớp học ám sát")
\(\left(x-\frac{3}{5}\right):\left(x-0,5\right)=\frac{2}{3}\)
\(x-\frac{3}{5}=\frac{2}{3}\left(x-0,5\right)\)
\(x-\frac{3}{5}=\frac{2}{3}x-\frac{1}{3}\)
\(\frac{2}{3}x-x=\frac{1}{3}-\frac{3}{5}\)
\(-\frac{1}{3}x=-\frac{4}{15}\)
\(x=\frac{4}{5}\)