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3x+1+2.3x-1=99
=>3x-1(32+2)=99
=>3x-1.11=99
=>3x-1=99:11=9=32
=.x-1=2
=>x=3
Vậy x=3
b,3.2x+2+3.2x=120
=>3.2x(22+1)=120
=>3.2x.5=120
=>3.2x=120:5
=>2x=24:3=8=23
=>x=3
Vậy x=3
=
a)197-9(x+3)=80
=>9(x+3)=197-80
=>9(x+3)=117
=>x+3=117:9
=>x+3=13
=>x=13-3=10
b)7(x-14)+35=56
=>7(x+14)=56-35
=>7(x+14)=21
=>x+14=21/7
=>x+14=3
=>x=3-14=(-11)
c)2.3x-1=54
=>3x-1=54:2
=>3x-1=27
=>3x-1=33
=>x-1=3
=>x=3+1=4
d)3.2x-1=24
=>2x-1=24:3
=>2x-1=8
=>2x-1=23
=>x-1=3
=>x=3+1=4
a, 2.3x = 18
=> 3x = 9 = 32
=> x = 2
b, 2x + 3.2x + 4.2x = 32
=> 2x.(1+3+4) = 32
=> 2x . 8 = 32
=> 2x = 4 = 22
=> x = 2
c, 3x + 4x = 5x
Câu này mik chưa nghĩ ra
a)1.3^x=18
=>3^x=18:2=9
=>3^x=3^2
=>x=2
b)=>2^x.(1+3+4)=32
=>2^x.8=32
=>2^x=4
=>2^x=2^2
=>x=2
`#3107`
b)
`2.3^x = 162`
`\Rightarrow 3^x = 162 \div 2`
`\Rightarrow 3^x = 81`
`\Rightarrow 3^x = 3^4`
`\Rightarrow x = 4`
Vậy, `x = 4`
c)
`(2x - 15)^5 = (2 - 15)^3`
\(\Rightarrow \)`(2x - 15)^5 - (2x - 15)^3 = 0`
\(\Rightarrow \)`(2x - 15)^3 . [ (2x - 15)^2 - 1] = 0`
\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=15\\\left(2x-15\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x-15=1\\2x-15=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x=16\\2x=-14\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=-7\end{matrix}\right.\)
Vậy, `x \in`\(\left\{-7;8;\dfrac{15}{2}\right\}.\)
`d)`
\(3^{x+2}-5.3^x=?\) Bạn ghi tiếp đề nhé!
`e)`
\(7\cdot4^{x-1}+4^{x-1}=23?\)
\(4^{x-1}\cdot\left(7+1\right)=23\\ \Rightarrow4^{x-1}\cdot8=23\\ \Rightarrow4^{x-1}=\dfrac{23}{8}\)
Bạn xem lại đề!
`f)`
\(2\cdot2^{2x}+4^3\cdot4^x=1056\)
\(\Rightarrow2\cdot2^{2x}+\left(2^2\right)^3\cdot\left(2^2\right)^x=1056\\ \Rightarrow2\cdot2^{2x}+2^6\cdot2^{2x}=1056\\ \Rightarrow2^{2x}\cdot\left(2+2^6\right)=1056\\ \Rightarrow2^{2x}\cdot66=1056\\ \Rightarrow2^{2x}=1056\div66\\ \Rightarrow2^{2x}=16\\ \Rightarrow2^{2x}=2^4\\ \Rightarrow2x=4\\ \Rightarrow x=2\)
Vậy, `x = 2`
_____
\(10 -{[(x \div 3+17) \div 10+3.2^4] \div 10}=5\)
\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)
\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)
\(\Rightarrow\left(x\div3+17\right)\div10+48=50\)
\(\Rightarrow\left(x\div3+17\right)\div10=2\)
\(\Rightarrow x\div3+17=20\)
\(\Rightarrow x\div3=3\\ \Rightarrow x=9\)
Vậy, `x = 9.`
a, 7\(x\) - \(x\) = 521 : 519 + 3.22.7
6\(x\) = 53 + 3.4.7
6\(x\) = 125 + 12.7
6\(x\) = 125 + 84
6\(x\) = 209
\(x\) = 209 : 6
\(x\) = \(\dfrac{209}{6}\)
b; 11\(x\) - 7\(x\) + 34 : 33 = 54 + 2\(x\)
4\(x\) + 3 = 625 + 2\(x\)
4\(x\) - 2\(x\) = 625 - 3
2\(x\) = 622
\(x\) = 622 : 2
\(x\) = 311
c; 75 - 5.(\(x-3\))3 = 700
5.(\(x\) - 3)3 = 700 - 75
5.(\(x\) - 3)3 = - 625
(\(x\) - 30)3 = - 625 : 5
(\(x\) - 30)3 = - 125
(\(x-3\))3 = (-5)3
\(x\) - 3 = - 5
\(x\) = - 5 + 3
\(x\) = -2
d, 3.(2\(x\) - 1)2 = 75
(2\(x\) - 1)2 = 75 : 3
(2\(x\) - 1)2 = 25
\(\left[{}\begin{matrix}2x-1=-5\\2x-1=5\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-5+1\\2x=5+1\end{matrix}\right.\)
\(\left[{}\begin{matrix}2x=-4\\2x=6\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\)
2.9-x-3.4=8.3
18-x-12=24
6-x=24
x=6-24
x=-18
Vậy x=-18
Học tốt nha -Kết bạn facebook nguyenminh không dấu và ko avatar
(x+28):13=25.2
(x+28):13=50
(x+28) = 650
x = 622
vậy: x = 622
nhớ k mình nha
CHÚC BẠN HOK TỐT
\(\left(x+28\right):13=25\cdot2\)
\(\left(x+28\right):13=50\)
\(x+28=50\cdot13\)
\(x+28=650\)
\(x=650-28\)
\(x=622\)
Vậy \(x=622\)
\(\Rightarrow\left(x+x+x+x\right)+\left(3,2+1,8+1,7+2,3\right)=25,2\)
\(\Rightarrow4x+9=25,2\)
\(\Rightarrow4x=16,2\Rightarrow x=4,05\)