Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(M(x) = A(x) + B(x) \\= 4{x^4} + 6{x^2} - 7{x^3} - 5x - 6 - 5{x^2} + 7{x^3} + 5x + 4 - 4{x^4} \\=(4x^4-4x^4)+(-7x^3+7x^3)+(6x^2-5x^2)+(-5x+5x)+(-6+4)\\= {x^2} - 2.\)
b) \(A(x) = B(x) + C(x) \Rightarrow C(x) = A(x) - B(x)\)
\(\begin{array}{l}C(x) = A(x) - B(x)\\ = 4{x^4} + 6{x^2} - 7{x^3} - 5x - 6 - ( - 5{x^2} + 7{x^3} + 5x + 4 - 4{x^4})\\ = 4{x^4} + 6{x^2} - 7{x^3} - 5x - 6 + 5{x^2} - 7{x^3} - 5x - 4 + 4{x^4}\\ =(4x^4+4x^4)+(-7x^3-7x^3)+(6x^2+5x^2)+(-5x-5x)+(-6-4)\\= 8{x^4} - 14{x^3} + 11{x^2} - 10x - 10\end{array}\)
Theo đề bài ta có \(M(x) = 2{x^4} - 5{x^3} + 7{x^2} + 3x\)
\(\begin{array}{l}M(x) + Q(x) = 6{x^5} - {x^4} + 3{x^2} - 2\\ \Rightarrow Q(x) = (6{x^5} - {x^4} + 3{x^2} - 2) - (2{x^4} - 5{x^3} + 7{x^2} + 3x)\\ \Rightarrow Q(x) = 6{x^5} - {x^4} + 3{x^2} - 2 - 2{x^4} + 5{x^3} - 7{x^2} - 3x\\Q(x) = 6{x^5} - 3{x^4} + 5{x^3} - 4{x^2} - 3x - 2\end{array}\)
Theo đề bài ta có :
\(\begin{array}{l}N(x) - M(x) = - 4{x^4} - 2{x^3} + 6{x^2} + 7\\ \Rightarrow N(x) = - 4{x^4} - 2{x^3} + 6{x^2} + 7 + 2{x^4} - 5{x^3} + 7{x^2} + 3x\\ \Rightarrow N(x) = - 2{x^4} - 7{x^3} + 13{x^2} + 3x + 7\end{array}\)
\(\left|\frac{5}{7}x-4\right|< \frac{2}{7}\)
\(\Leftrightarrow-\frac{2}{7}< \frac{5}{7}x-4< \frac{2}{7}\)
\(\Leftrightarrow5\frac{1}{5}< x< 6\)
Ta có : \(\left|\frac{5}{7}x-4\right|< \frac{2}{7}\)
\(\Rightarrow\frac{-2}{7}< \frac{5}{7}x-4< \frac{2}{7}\)
\(\Rightarrow\frac{-2}{7}+4< \frac{5}{7}x-4+4< \frac{2}{7}+4\)
\(\Rightarrow\frac{26}{7}< \frac{5x}{7}< \frac{30}{7}\)
\(\Rightarrow26< 5x< 30\)
\(\Rightarrow5,2< x< 6\)
\(|\frac{5}{7}x-4|< \frac{2}{7}\Rightarrow\frac{-2}{7}< \frac{5}{7}x-4< \frac{2}{7}\Rightarrow\frac{-2}{7}+4< \frac{5}{7}x-4+4< \frac{2}{7}+4\Rightarrow\frac{26}{7}< \frac{5x}{7}< \frac{30}{7}\)
=> 26 < 5x < 30 => 5,2 < x < 6
\(\left|\frac{6}{7}x-4\right|< \frac{2}{7}\)
\(\Leftrightarrow-\frac{2}{7}< \frac{5}{7}x-4< \frac{2}{7}\)
\(\Leftrightarrow5\frac{1}{5}< x< 6\)
=> -2/7 < 5/7.x-4 < 2/7
=> -2/7+4 < 5/7.x < 2/7+4
=> 26/7 < 5/7.x < 30/7
=> 26/7 : 5/7 < x < 30/7 : 5/7
=> 26/5 < x < 6
Tk mk nha
\(\left|\dfrac{5}{7}x-4\right|< \dfrac{2}{5}\)
\(\Rightarrow-\dfrac{2}{5}< \dfrac{5}{7}x-4< \dfrac{2}{5}\)
\(\Rightarrow-\dfrac{2}{5}+4< \dfrac{5}{7}x-4+4< \dfrac{2}{5}+4\)
\(\Rightarrow\dfrac{18}{5}< \dfrac{5}{7}x< \dfrac{22}{5}\)
\(\Rightarrow\dfrac{18}{5}:\dfrac{5}{7}< \dfrac{5}{7}x:\dfrac{5}{7}< \dfrac{22}{5}:\dfrac{5}{7}\)
\(\Rightarrow\dfrac{126}{25}< x< \dfrac{154}{25}\)