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a) \(2^{4x+1}-8^{x+2}=0\)\(\Leftrightarrow2^{4x+1}-2^{3\left(x+2\right)}=0\)
\(\Leftrightarrow2^{4x+1}-2^{3x+6}=0\)\(\Leftrightarrow2^{4x+1}=2^{3x+6}\)
\(\Leftrightarrow4x+1=3x+6\)\(\Leftrightarrow4x-3x=6-1\)\(\Leftrightarrow x=5\)
Vậy \(x=5\)
b) \(3^2.9^{2x}=27^{x+3}\)\(\Leftrightarrow3^2.3^{2.2x}=3^{3\left(x+3\right)}\)\(\Leftrightarrow3^2.3^{4x}=3^{3x+9}\)
\(\Leftrightarrow3^{2+4x}=3^{3x+9}\)\(\Leftrightarrow2+4x=3x+9\)\(\Leftrightarrow4x-3x=9-2\)\(\Leftrightarrow x=7\)
Vậy \(x=7\)
c) \(8^{2x}.64^2=16^{x+4}\)\(\Leftrightarrow2^{3.2x}.2^{6.2}=2^{4\left(x+4\right)}\)\(\Leftrightarrow2^{6x}.2^{12}=2^{4\left(x+4\right)}\)
\(\Leftrightarrow2^{6x+12}=2^{4x+16}\)\(\Leftrightarrow6x+12=4x+16\)\(\Leftrightarrow6x-4x=16-12\)
\(\Leftrightarrow2x=4\)\(\Leftrightarrow x=2\)
Vậy \(x=2\)
\(a)\left|x-9\right|\cdot(-8)=-16\)
\(\Rightarrow\left|x-9\right|=-16\div(-8)\)
\(\Rightarrow\left|x-9\right|=2\)
\(\Rightarrow x-9=\pm2\)
Lập bảng :
x - 9 | 2 | -2 |
x | 11 | 7 |
Vậy : \(x\in\left\{11;7\right\}\)
\(b)\left|4-5x\right|=24\)
\(\Rightarrow4-5x=\pm24\)
Lập bảng :
4 - 5x | 24 | -24 |
x | -4 | \(\frac{28}{5}\) |
Mà \(x< 0\)nên x = -4
a/ \(\left|2x-2\right|=x+18\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-2=x+18\\2x-2=-x-8\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-x=18+2\\2x+x=-8+2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=20\\3x=-6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=20\\x=-2\end{matrix}\right.\)
Vậy ...
b/ \(\left|2x-8\right|+4x=16\)
\(\Leftrightarrow\left|2x-8\right|=16-4x\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-8=16-4x\\2x-8=-16+4x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+4x=16+8\\-8+16=4x-2x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}6x=24\\8=2x\end{matrix}\right.\)
\(\Leftrightarrow x=4\)
Vậy..
a, |3x - 6| + 4x + 3 = 12
|3x - 6| = 12 - 3 - 4x
|3x - 6| = 9 - 4x
TH1: 3x - 6 = 9 - 4x ⇔ 3x + 4x = 9 + 6 ⇔ 7x = 15 ⇔ x = 15/7
TH2: 3x - 6 = 4x - 9 ⇔ 3x - 4x = -9 + 6 ⇔ -x = -3 ⇔ x = 3.
b, |6x - 12| + 3x - 1 = 43
|6x - 12| = 43 + 1 - 3x
|6x - 12| = 44 - 3x
TH1: 6x - 12 = 44 - 3x ⇔ 6x + 3x = 44 + 12 ⇔ 9x = 56 ⇔ x = 6.
TH2: 6x - 12 = 3x - 44 ⇔ 6x - 3x = -44 + 12 ⇔ 3x = -32 ⇔ x = -32/3.
c, |8 - 4x| + 7x - 5 = 16 - 2x
|8 - 4x| = (16 + 5) + (-2x - 7x)
|8 - 4x| = 21 - 9x
TH1: 8 - 4x = 21 - 9x ⇔ -4x + 9x = 21 - 8 ⇔ 5x = 13 ⇔ x = 13/5
TH2: 8 - 4x = 9x - 21 ⇔ -4x - 9x = -21 - 8 ⇔ -15x = -29 ⇔ x = 29/15
1a) x - 7 = -18
=> x = -18 + 7
=> x = -11
b) -2x + 8 = -24
=> -2x = -24 - 8
=> -2x = -32
=> x = -32 : (-2)
=> x = 16
c) 4 - 2x = 59
=> 2x = 4 - 59
=> 2x = -55
=> x = -55 : 2
=> x = -27,5
d) -36 - x = 59
=> x = -36 - 59
=> x = -95
k) -81 : x = (-3)
=> x = -81 : (-3)
=> x = 27
g) -16 : x = 2
=> x = -16 : 2
=> x = -8
m) (6 - 27) - (3 - x) = (-7) . (-8)
=> -21 - (3 - x) = 56
=> 3 - x = -21 - 56
=> 3 - x = -77
=> x = 3 + 77
=> x = 80
a) \(\left|2x-2\right|=x+18\)
\(\Rightarrow\left[{}\begin{matrix}2x-2=x+18\\2x-2=-x-18\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x-x=2+18\\2x+x=2-18\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=20\\3x=-16\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=20\\x=\dfrac{-16}{3}\end{matrix}\right.\) Vậy x = 20 hoặc x = \(\dfrac{-16}{3}\)
b) \(\left|2x-8\right|+4x=16\) \(\Rightarrow\left|2x-8\right|=16-4x\)
\(\Rightarrow\left[{}\begin{matrix}2x-8=16-4x\\2x-8=-16+4x\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}2x+4x=16+8\\2x-4x=-16+8\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}6x=24\\-2x=-8\end{matrix}\right.\) \(\Rightarrow x=4\) (cả 2 trường hợp bằng 4)
Vậy x = 4
Bạn có thể thử lại bằng máy tính nếu ko chắc chắn (mình có thử rồi)
c) (4x - 8)[x + (-3)] = 0
=> 4(x - 2)(x - 3) = 0
=> (x - 2)(x - 3) = 0
=> x - 2 = 0 hoặc x - 3 = 0
+) x - 2 = 0 => x = 2
+) x - 3 = 0 => x = 3
Vậy x \(\in\){2;3}
11(x - 6) = 4x + 11
=> 11x - 66 = 4x + 11
=> 11x - 4x = 11 + 66
=> 7x = 77
=> x = 77/7
=> x = 11
\(a,2\cdot\left(4x-2x\right)-7x=16\\ 2\cdot2x-7x=16\\ 4x-7x=16\\ -3x=16\\ x=-16:3\\ x=\dfrac{-16}{3}\\ b,-2\left[x+\left(-7\right)\right]+\left(x+3\right)=12\\ -2\cdot x+\left(-2\right)\cdot\left(-7\right)+x+3=12\\ -2x+x+14+3=12\\ -x+17=12\\ -x=-5\\ \Rightarrow x=5\\ c,10\cdot\left(x-7\right)=8\left(x-4\right)+x\\ 10x-10\cdot7=8x-8\cdot4+x\\ 10x-70=9x-32\\ 10x-70+32=9x\\ 10x-38=9x\\ \Rightarrow x=38\)
b) 2x = 8 x 4
2x = 32
x = 32 : 2
x = 16
c) 4x = 16
x = 16 : 4
x = 4
b)2x:4=8 c)4x=16
2x=8.4 x=16:4
2x=32 x=4
x=32:2
x=16