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\(a,3,8:2x=\frac{1}{4}:2\frac{2}{3}\)
\(\Leftrightarrow3,8:2x=\frac{3}{32}\)
\(\Leftrightarrow2x=3,8:\frac{3}{32}\)
\(\Leftrightarrow2x=\frac{608}{15}\)
\(\Leftrightarrow x=\frac{304}{15}\)
\(b,0,25x:3=\frac{5}{6}:0,125\)
\(\Leftrightarrow0,25x:3=\frac{20}{3}\)
\(\Leftrightarrow0,25x=20\)
\(\Leftrightarrow x=80\)
\(c,0,01:2,5=0,75x:0,75\)
\(\Leftrightarrow0,75x:0,75=\frac{1}{250}\)
\(\Leftrightarrow x=\frac{1}{250}\)
Mik lm hơi tắt chỗ nào chw hiểu thì hỏi mik nhé
c) \(x:\left(-2,14\right)=\left(-3,12\right):1,2\)
=> \(x:\left(-2,14\right)=-2,6\)
=> \(x=\left(-2,6\right).\left(-2,14\right)\)
=> \(x=5,564\)
Vậy \(x=5,564.\)
d) \(2\frac{2}{3}:x=2\frac{1}{2}:\left(-0,06\right)\)
=> \(\frac{8}{3}:x=\frac{25}{12}:\left(-\frac{3}{50}\right)\)
=> \(\frac{8}{3}:x=-\frac{625}{18}\)
=> \(x=\frac{8}{3}:\left(-\frac{625}{18}\right)\)
=> \(x=-\frac{48}{625}\)
Vậy \(x=-\frac{48}{625}.\)
Chúc bạn học tốt!
0,01 : 2,5 = (0,75x) : 0,75
⇔ (0,75x).2,5 = 0,01.0,75
⇔ (0,75x) = (0,01.0,75) : 2,5
⇔ 0,75x = 0,003
⇔ x = 0,003 : 0,75 ⇔ x = 0,004
c) (0.01):2,5=(0,75x).(0,75)
0,004 =(0,75x).(0,75)
=> x=0.0071
Đề này bn xem lại coi có đúng k
a)\(\frac{x}{64}=-\frac{16}{x}\Rightarrow x^2=-16\cdot64\)
\(\Rightarrow x^2=-1024\)
Do \(x^2\ge0>-1024=VP\)
=>x vô nghiệm
b)0,01: 2,5= (0,75x) : 0,75
=>0,004=0,75:0,75*x
=>0,004=x
Vậy x=0,004
a) Ta có: \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
\(\Leftrightarrow x^2=\left(-15\right)\cdot\left(-60\right)=900\)
hay \(x\in\left\{30;-30\right\}\)
Vậy: \(x\in\left\{30;-30\right\}\)
b) Ta có: \(\left|x\right|+0.573=2\)
\(\Leftrightarrow\left|x\right|=1.427\)
hay \(x\in\left\{1.427;-1.427\right\}\)
Vậy: \(x\in\left\{1.427;-1.427\right\}\)
c) Ta có: \(\left|x+\dfrac{1}{3}\right|-4=-1\)
\(\Leftrightarrow\left|x+\dfrac{1}{3}\right|=3\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{8}{3};-\dfrac{10}{3}\right\}\)
d) Ta có: \(0.01:2.5=\left(0.75x\right):0.75\)
\(\Leftrightarrow\dfrac{0.75\cdot x}{0.75}=\dfrac{0.01}{2.5}\)
\(\Leftrightarrow x=\dfrac{1}{250}\)
Vậy: \(x=\dfrac{1}{250}\)
a ) \(\frac{-2}{x}=\frac{x}{\frac{8}{25}}\)
\(\Leftrightarrow x^2=-2.-\frac{16}{25}\)
\(\Leftrightarrow x^2=\frac{16}{25}\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\sqrt{\frac{16}{25}}\\x=-\sqrt{\frac{16}{25}}\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{4}{5}\\x=-\frac{4}{5}\end{array}\right.\)
Vậy ......................................